Question
Solve the system of Equation (x,y) by the method of elimination:
x + 12y = 15
–x –2y = -5
- (3,-1)
- (3,1)
- (1,-3)
- (-3,-1)
Hint:
Here we have to solve the system of equation by elimination. The equation are x+12y = 15 and –x−2y = -5. In elimination method we have to multiply in both equation by number which is lowest common multiple for one of the variable. Then perform the addition or subtraction to eliminate the variable and substitute the that variable in equation and find the other equation.
The correct answer is: (3,1)
Here we have to solve the system of equation that is x+12y = 15 and -x−2y = -5. by elimination method.
Firstly we have two equations,
x+12y = 15 ...(1)
-x−2y = -5 ...(2)
Adding (1) and (2),
y = 1
Substituting y=1 in (1), we get
x+12y=15
x + 12(1)=15
x= 3
Put x= 3 in eq (1)
x+12y = 15
3 + 12y = 15
12y = 15 - 3
Divide both side by 12.
y = 1
Therefore, the solution of following pair linear equation is x= 3 and y = 1.
The correct answer is x = 3 and y = 1.
In this question , we have to solve the system of equation by elimination method. In elimination method you have two equation. we have to multiply in both equation by number which is lowest common multiple for one of the variable. Then perform the addition or subtraction to eliminate the variable and substitute the that variable in equation and find the other equation.
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