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The body surface area (BSA) of a human being is used to determine doses of medication. The formula for finding BSA is BSA = $square root of fraction numerator H cross times M over denominator 3600 end fraction end root$ ,where H is the height in centimeters and M is the mass in kilograms. A doctor calculates a particular dose of medicine for a patient whose BSA is less than 1.9. If the patient is 160 cm tall, what must the mass of the person be for the dose to be appropriate?

hint Hint:

Substitute in the equation and solve.

The correct answer is: 81.225

Complete step by step solution:
Here, BSA < 1.9 and H = 160cm
Given that the formula for BSA = $square root of fraction numerator H cross times M over denominator 3600 end fraction end root$
$not stretchy rightwards double arrow square root of fraction numerator 160 cross times M over denominator 3600 end fraction end root less than 1.9$
On squaring both the sides, we get $fraction numerator 160 cross times M over denominator 3600 end fraction less than 3.61$
$table attributes columnspacing 1em end attributes row cell space space space space space space space not stretchy rightwards double arrow 160 M less than 12996 end cell row cell not stretchy rightwards double arrow M less than 81.225 end cell end table$
So, the mass of the person must be less than 81.225 for the dose to be appropriate.

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Substitute in the equation and solve.

The correct answer is: 81.225

Complete step by step solution:Here, BSA < 1.9 and H = 160cmGiven that the formula for BSA = On squaring both the sides, we get So, the mass of the person must be less than 81.225 for the dose to be appropriate.

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A Saving account has a balance of $1 . Savings plan A will add $1000 to an account each month , and plan B will double the amount each month ?
a. Which plan is better in the short run ? for How long , Explain.
b. Which plan is better in the long run ? Explain.

A Saving account has a balance of $1 . Savings plan A will add $1000 to an account each month , and plan B will double the amount each month ?
a. Which plan is better in the short run ? for How long , Explain.
b. Which plan is better in the long run ? Explain.

Solve the radical equation $13 minus fourth root of x equals 10$ Check for extraneous solutions

Solve the radical equation $13 minus fourth root of x equals 10$ Check for extraneous solutions

Compare the functions f(x)= 3X+2 , g(x)= 2x²+3 and h(x)= 2^x . Show that as x increases , h(x) will eventually exceed f(x) and g(x).

Compare the functions f(x)= 3X+2 , g(x)= 2x²+3 and h(x)= 2^x . Show that as x increases , h(x) will eventually exceed f(x) and g(x).

Solve the radical equation $square root of 15 minus x end root minus square root of 6 x end root equals negative 3$

Solve the radical equation $square root of 15 minus x end root minus square root of 6 x end root equals negative 3$

Solve the radical equation $square root of 6 x minus 20 end root minus x equals negative 6$ . Check for extraneous solutions

Solve the radical equation $square root of 6 x minus 20 end root minus x equals negative 6$ . Check for extraneous solutions

Use the functions shown :
a. Evaluate each function for x=6 , x=8 and x=12
b. When will function h exceed function f and function g ?

Use the functions shown :
a. Evaluate each function for x=6 , x=8 and x=12
b. When will function h exceed function f and function g ?

Solve the radical equation $square root of x plus 4 end root minus square root of 3 x end root equals negative 2$ . Check for extraneous solutions

Solve the radical equation $square root of x plus 4 end root minus square root of 3 x end root equals negative 2$ . Check for extraneous solutions

Solve the radical equation $square root of 5 x plus 1 end root plus 1 equals x$ . Check for extraneous solutions

Solve the radical equation $square root of 5 x plus 1 end root plus 1 equals x$ . Check for extraneous solutions

Solve the radical equation $square root of 2 x end root equals 12$ . Check for extraneous solutions

Solve the radical equation $square root of 2 x end root equals 12$ . Check for extraneous solutions