Find the axis of symmetry, vertex and y-intercept of the function
f(x) = 0.4x² + 1.6x

The correct answer is: 0

This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)= 0.4x² + 1.6x, a= 0.4, b= 1.6, and c= 0. So, the equation for the axis of symmetry is given by

x = −(1.6)/2(0.4)

x = -1.6/0.8

x = -2
The equation of the axis of symmetry for f(x)= 0.4x² + 1.6x is x = -2.
The x coordinate of the vertex is the same:

h = -2
The y coordinate of the vertex is :

k = f(h)

k = 0.4(h)² + 1.6h

k = 0.4(-2)² + 1.6(-2)

k = 1.6 – 3.2

k = -1.6
Therefore, the vertex is (-2 , -1.6)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.

y = 0.4(0)² + 1.6(0)

y = 0 + 0

y = 0
Therefore, Axis of symmetry is x = -2
Vertex is ( -2 , -1.6)
Y- intercept is 0.