Maths-
General
Easy

Question

A non zero vector stack a with ‾ on top is parallel to the line of intersection of the plane determined by the vectors i with ‾ on top comma i with ‾ on top plus j with ‾ on top and the plane determined by the vectors i with ‾ on top minus j with ‾ on top comma i with ‾ on top plus k with ‾ on top then the angle between stack a with ‾ on top and left parenthesis i with ‾ on top minus 2 j with ‾ on top plus 2 k with ‾ on top right parenthesis is horizontal ellipsis..

  1. fraction numerator pi over denominator 6 end fraction    
  2. fraction numerator pi over denominator 4 end fraction    
  3. fraction numerator pi over denominator 3 end fraction    
  4. fraction numerator pi over denominator 2 end fraction    

hintHint:

We have to find the components of the vector parallel to the intersection of two planes. The planes are given using two vectors each. We have to find the angle between the parallel vector and another given vector. We will find the value of parallel vector by finding the line of intersection. Then, we will take the dot product.

The correct answer is: fraction numerator pi over denominator 4 end fraction


    The parallel vector is a with rightwards arrow on top
    We have two vectors for each plane. Let the planes be Q and R.
    The vectors for Q are as follows:
    i with hat on top
i with hat on top space plus space j with hat on top
    The vectors for R are as follows:
    i with hat on top space minus space j with hat on top
i with hat on top space plus space k with hat on top
    Let the another given vector be denoted by
    B with rightwards arrow on top equals i with hat on top minus 2 j with hat on top plus 2 k with hat on top
    We will find the normal to the planes by taking the cross product of the respective vectors.
    Then by taking the cross product of normals, we will get the vector for line of intersection of two planes.
    Let the normal to the first plane be denoted as stack n subscript 1 with rightwards arrow on top space
    The normal to the second plane is denoted by n with rightwards arrow on top subscript 2
    We will find the normals now
    stack n subscript 1 with rightwards arrow on top space equals left parenthesis i with hat on top right parenthesis space cross times left parenthesis i with hat on top space plus j with hat on top right parenthesis
space space space space equals open vertical bar table row cell i with hat on top end cell cell j with hat on top end cell cell k with hat on top end cell row 1 0 0 row 1 1 0 end table close vertical bar
space space space space equals i with hat on top left parenthesis 0 right parenthesis minus j with hat on top left parenthesis 0 right parenthesis space plus k with hat on top left parenthesis 1 minus 0 right parenthesis
space space space space equals k with hat on top
stack n subscript 2 with rightwards arrow on top space equals left parenthesis i with hat on top minus j with hat on top right parenthesis space cross times left parenthesis i with hat on top space plus space k with hat on top right parenthesis
space space space space space equals open vertical bar table row cell i with hat on top end cell cell j with hat on top end cell cell k with hat on top end cell row 1 cell negative 1 end cell 0 row 1 0 1 end table close vertical bar
space space space space space equals i with hat on top left parenthesis negative 1 minus 0 right parenthesis space minus j with hat on top left parenthesis 1 space minus 0 right parenthesis plus k with hat on top left square bracket 0 minus left parenthesis negative 1 right parenthesis right square bracket
space space space space space equals negative i with hat on top space minus j with hat on top space plus k with hat on top
    Now, to find the line of intersection we will take the cross product of normals.
    Let the line be denoted as A with rightwards harpoon with barb upwards on top
    A with rightwards arrow on top space equals stack n subscript 1 with rightwards arrow on top space cross times stack n subscript 2 with rightwards arrow on top
space space space space equals open vertical bar table row cell i with hat on top end cell cell j with hat on top end cell cell k with hat on top end cell row 0 0 1 row cell negative 1 end cell cell negative 1 end cell 1 end table close vertical bar
space space space space equals i with hat on top open square brackets 0 space minus left parenthesis negative 1 right parenthesis close square brackets space minus j with hat on top open square brackets 0 minus left parenthesis negative 1 right parenthesis close square brackets space plus k with hat on top left parenthesis 0 right parenthesis
space space space equals i with hat on top space minus j with hat on top
space
    A s space t h e space v e c t o r space a with rightwards arrow on top space i s space p a r a l l e l space t o space v e c t o r space A with rightwards arrow on top
w e space c a n space w r i t e
a with rightwards arrow on top space equals i with hat on top space minus j with hat on top
    The angle between the line of intersection and the given vector will be same as the angle between the vector a with rightwards arrow on top and the given vector.
    To find the angle between them, we will use the dot product.
    a with rightwards arrow on top. B with rightwards arrow on top space equals open vertical bar a close vertical bar open vertical bar B close vertical bar cos theta

R e a r r a n g e space f o r space cos theta
cos theta space equals fraction numerator a with rightwards arrow on top. B with left right arrow on top over denominator open vertical bar a close vertical bar open vertical bar B close vertical bar end fraction
space space space space space space space space space equals fraction numerator left parenthesis i with hat on top minus j with hat on top right parenthesis. left parenthesis i with hat on top minus 2 j with hat on top plus 2 k with hat on top right parenthesis over denominator square root of 1 plus 1 end root square root of 1 plus 4 plus 4 end root end fraction
space space space space space space space space space equals fraction numerator 1 plus 2 over denominator square root of 2 square root of 9 end fraction
space space space space space space space space space equals fraction numerator 3 over denominator 3 square root of 2 end fraction
space space space space space space space space space equals fraction numerator 1 over denominator square root of 2 end fraction
T a k e space cos space i n v e r s e space
theta space equals cos to the power of negative 1 end exponent left parenthesis fraction numerator 1 over denominator square root of 2 end fraction right parenthesis
theta space equals space pi over 4
    This is the required angle between the two vectors.

    For such questions, we should know how to find the normal to the plane. We should know how to find the line of intersection of two planes. And, we should know how to take a cross product.

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