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Maths-

General

Easy

Question

$increment A B C comma sin invisible function application A plus sin invisible function application B plus sin invisible function application C equals 1 plus square root of 2$ and $cos invisible function application A plus cos invisible function application plus cos invisible function application C equals square root of 2$ if the triangle is

Equilateral
Isosceles
Right angled
Right-angled isosceles

The correct answer is: Right-angled isosceles

If the triangle is equilateral
$sin invisible function application A plus sin invisible function application B plus sin invisible function application C equals fraction numerator 3 square root of 3 over denominator 2 end fraction$
If the triangle is isosceles, let $A equals 30 degree comma blank B equals 30 degree comma blank C equals 120 degree$
Then $comma sin invisible function application A plus sin invisible function application B plus sin invisible function application C equals 1 plus fraction numerator square root of 3 over denominator 2 end fraction$
If the triangle is right angled, let $A equals 90 degree comma blank B equals 30 degree comma blank C equals 60 degree$
Then, $sin invisible function application A plus sin invisible function application B plus sin invisible function application C equals fraction numerator 3 plus square root of 3 over denominator 2 end fraction$
If the triangle is right-angled isosceles, then one of the angles is $90 degree$ and the remaining two are $45 degree$ each, so that
$sin invisible function application A plus sin invisible function application B plus sin invisible function application C equals 1 plus square root of 2$
and $cos invisible function application A plus cos invisible function application B plus cos invisible function application C equals square root of 2$

Related Questions to study

ven $A equals sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application theta comma$ then for all real $theta$ ,

ven $A equals sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application theta comma$ then for all real $theta$ ,

$open parentheses 1 plus tan invisible function application alpha close parentheses open parentheses 1 plus tan invisible function application 4 alpha close parentheses equals 2 comma blank alpha element of open parentheses 0 comma blank pi divided by 16 close parentheses$ then $alpha$ is equal to

$open parentheses 1 plus tan invisible function application alpha close parentheses open parentheses 1 plus tan invisible function application 4 alpha close parentheses equals 2 comma blank alpha element of open parentheses 0 comma blank pi divided by 16 close parentheses$ then $alpha$ is equal to

Let $f open parentheses theta close parentheses equals sin invisible function application theta left parenthesis sin invisible function application theta plus sin invisible function application 3 theta right parenthesis.$ Then $f left parenthesis theta right parenthesis$ is

Let $f open parentheses theta close parentheses equals sin invisible function application theta left parenthesis sin invisible function application theta plus sin invisible function application 3 theta right parenthesis.$ Then $f left parenthesis theta right parenthesis$ is

parallel

The value of $tan invisible function application 9 degree minus tan invisible function application 27 degree minus tan invisible function application 63 degree plus tan invisible function application 81 degree blank i s$

The value of $tan invisible function application 9 degree minus tan invisible function application 27 degree minus tan invisible function application 63 degree plus tan invisible function application 81 degree blank i s$

If $blank sin invisible function application x plus cos invisible function application x equals fraction numerator square root of 7 over denominator 2 end fraction blank$ where $blank x element of A comma$ then $tan invisible function application fraction numerator x over denominator 2 end fraction blank$ is equal to

If $blank sin invisible function application x plus cos invisible function application x equals fraction numerator square root of 7 over denominator 2 end fraction blank$ where $blank x element of A comma$ then $tan invisible function application fraction numerator x over denominator 2 end fraction blank$ is equal to

If $fraction numerator 3 pi over denominator 4 end fraction less than alpha less than pi comma blank$ then $square root of 2 cot invisible function application alpha plus fraction numerator 1 over denominator sin to the power of 2 end exponent invisible function application alpha end fraction end root blank$ is equal to

If $fraction numerator 3 pi over denominator 4 end fraction less than alpha less than pi comma blank$ then $square root of 2 cot invisible function application alpha plus fraction numerator 1 over denominator sin to the power of 2 end exponent invisible function application alpha end fraction end root blank$ is equal to

parallel

Hydrogen burns in air with a

Hydrogen burns in air with a

Chemistry-General

Metal hydride on treatment with water gives

Metal hydride on treatment with water gives

Chemistry-General

Which is used hydrogen generators

Which is used hydrogen generators

Chemistry-General

parallel

Assertion:First ionization energy for nitrogen is lower than oxygen.
Reason :Across a period effective nuclear charge decreases.

Assertion:First ionization energy for nitrogen is lower than oxygen.
Reason :Across a period effective nuclear charge decreases.

Chemistry-General

Assertion :Outermost electronic configuration of most electropositive elements is ns² np³.
Reason :ns² np³is stable due to half filled subshell.

Assertion :Outermost electronic configuration of most electropositive elements is ns² np³.
Reason :ns² np³is stable due to half filled subshell.

Physics-General

Assertion :NO^– ion is isoelectronic with CN^– ion.
Reason :Isoelectronic ions have same number of elelctrons.

Assertion :NO^– ion is isoelectronic with CN^– ion.
Reason :Isoelectronic ions have same number of elelctrons.

Physics-General

parallel

Assertion :I.E. of ₇N is more than that of ₈O as well as ₆C.
Reason : This is due to difference in reactivity towards oxygen.

Assertion :I.E. of ₇N is more than that of ₈O as well as ₆C.
Reason : This is due to difference in reactivity towards oxygen.

Physics-General

Assertion :Ground state configuration of Cr is 3d⁵, 4s¹.
Reason : A set of half filled orbitals containing one electron each with their spin parallel provides extra stability to the system.

Assertion :Ground state configuration of Cr is 3d⁵, 4s¹.
Reason : A set of half filled orbitals containing one electron each with their spin parallel provides extra stability to the system.

Physics-General

Assertion :More is the electron affinity greater is the reducing character.
Reason : Reducing character depends on number of electrons gained.

Assertion :More is the electron affinity greater is the reducing character.
Reason : Reducing character depends on number of electrons gained.

Physics-General

parallel

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