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Easy

Question

Assertion : In any ABC, minimum value of fraction numerator r subscript 1 end subscript plus r subscript 2 end subscript plus r subscript 3 end subscript over denominator r end fractionis 9.
Reason : A.M.  G.M.

  1. If both (A) and (R) are true, and (R) is the correct explanation of (A).  
  2. If both (A) and (R) are true but (R) is not the correct explanation of (A).  
  3. If (A) is true but (R) is false.  
  4. If (A) is false but (R) is true.  

The correct answer is: If both (A) and (R) are true but (R) is not the correct explanation of (A).


    Both are correct but reason is not correct explanation
     r1 = fraction numerator capital delta over denominator s minus a end fraction, r2 = fraction numerator capital delta over denominator s minus b end fraction, r3 = fraction numerator capital delta over denominator s minus c end fraction
    fraction numerator 1 over denominator r subscript 1 end subscript end fraction+fraction numerator 1 over denominator r subscript 2 end subscript end fraction+fraction numerator 1 over denominator r subscript 3 end subscript end fraction= fraction numerator 3 s minus left parenthesis a plus b plus c right parenthesis over denominator capital delta end fraction= fraction numerator s over denominator capital delta end fraction= fraction numerator 1 over denominator r end fraction
     A.M.  H.M.
    r1 + r2 + r3 fraction numerator 3 over denominator fraction numerator 1 over denominator r subscript 1 end subscript end fraction plus fraction numerator 1 over denominator r subscript 2 end subscript end fraction plus fraction numerator 1 over denominator r subscript 3 end subscript end fraction end fraction
    fraction numerator r subscript 1 end subscript plus r subscript 2 end subscript plus r subscript 3 end subscript over denominator r end fraction 9

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