Maths-
General
Easy

Question

Consider the system of equation x plus y plus z equals 6 comma blank x plus 2 y plus 3 z equals 10 and x plus 2 y plus lambda z equals mu
Statement 1 If the system has infinite number of solutions, then mu equals 10
Statement 2: The determinant open vertical bar table row 1 1 6 row 1 2 10 row 1 2 mu end table close vertical bar equals 0 for mu equals 10

  1. Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1    
  2. Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1    
  3. Statement 1 is True, Statement 2 is False    
  4. Statement 1 is False, Statement 2 is True    

The correct answer is: Statement 1 is True, Statement 2 is True; Statement 2 is not correct explanation for Statement 1


    Let increment equals open vertical bar table row 1 1 1 row 1 2 3 row 1 2 lambda end table close vertical bar equals 0 rightwards double arrow blank lambda equals 3. Now,
    increment subscript 1 end subscript equals open vertical bar table row 6 1 1 row 10 2 3 row mu 2 lambda end table close vertical bar
    equals open vertical bar table row 6 1 1 row 10 2 3 row mu 2 3 end table close vertical bar equals blank mu minus 10
    increment subscript 2 end subscript equals open vertical bar table row 1 6 1 row 1 10 3 row 1 cell blank mu end cell lambda end table close vertical bar equals open vertical bar table row 1 6 1 row 1 10 3 row 1 cell blank mu end cell 3 end table close vertical bar equals 20 minus 2 blank mu
    increment subscript 3 end subscript equals open vertical bar table row 1 1 6 row 1 2 10 row 1 2 mu end table close vertical bar equals mu minus 10
    Clearly, for mu equals 10, all of increment subscript 1 end subscript comma blank increment subscript 2 end subscript comma blank increment subscript 3 end subscript are zero

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