Maths-
General
Easy

Question

If A subscript 1 end subscript comma blank B subscript 1 end subscript comma blank C subscript 1 end subscript comma blank horizontal ellipsis are, respectively, the cofactors of the elementsa subscript 1 end subscript comma blank b subscript 1 end subscript comma blank c subscript 1 end subscript comma blank horizontal ellipsis of the determinant increment equals open vertical bar table row cell a subscript 1 end subscript end cell cell b subscript 1 end subscript end cell cell c subscript 1 end subscript end cell row cell a subscript 2 end subscript end cell cell b subscript 2 end subscript end cell cell c subscript 2 end subscript end cell row cell a subscript 3 end subscript end cell cell b subscript 3 end subscript end cell cell c subscript 3 end subscript end cell end table close vertical bar comma blank increment not equal to 0, then the value of open vertical bar table row cell B subscript 2 end subscript end cell cell C subscript 2 end subscript end cell row cell B subscript 3 end subscript end cell cell C subscript 3 end subscript end cell end table close vertical bar is equal to

  1. a subscript 1 end subscript superscript 2 end superscript increment    
  2. a subscript 1 end subscript superscript blank increment    
  3. a subscript 1 end subscript superscript blank increment to the power of 2 end exponent    
  4. a subscript 1 end subscript superscript 2 end superscript increment to the power of 2 end exponent    

The correct answer is: a subscript 1 end subscript superscript blank increment


    B subscript 2 end subscript equals a subscript 1 end subscript c subscript 3 end subscript minus a subscript 3 end subscript c subscript 1 end subscript comma blank C subscript 2 end subscript equals negative left parenthesis a subscript 1 end subscript b subscript 3 end subscript minus a subscript 3 end subscript b subscript 1 end subscript right parenthesis
    B subscript 3 end subscript equals negative open parentheses a subscript 1 end subscript c subscript 2 end subscript minus a subscript 2 end subscript c subscript 1 end subscript close parentheses comma blank C subscript 3 end subscript equals a subscript 1 end subscript b subscript 2 end subscript minus a subscript 2 end subscript b subscript 1 end subscript
    therefore open vertical bar table row cell B subscript 2 end subscript end cell cell C subscript 2 end subscript end cell row cell B subscript 3 end subscript end cell cell C subscript 2 end subscript end cell end table close vertical bar equals open vertical bar table row cell a subscript 1 end subscript c subscript 3 end subscript minus a subscript 3 end subscript c subscript 1 end subscript end cell cell negative a subscript 1 end subscript b subscript 3 end subscript plus a subscript 3 end subscript b subscript 1 end subscript end cell row cell negative a subscript 1 end subscript c subscript 2 end subscript plus a subscript 2 end subscript c subscript 1 end subscript end cell cell a subscript 1 end subscript b subscript 2 end subscript minus a subscript 2 end subscript b subscript 1 end subscript end cell end table close vertical bar
    equals open vertical bar table row cell a subscript 1 end subscript c subscript 3 end subscript end cell cell negative a subscript 1 end subscript b subscript 3 end subscript end cell row cell negative a subscript 1 end subscript c subscript 2 end subscript end cell cell a subscript 1 end subscript b subscript 2 end subscript end cell end table close vertical bar plus open vertical bar table row cell a subscript 1 end subscript c subscript 3 end subscript end cell cell a subscript 3 end subscript b subscript 1 end subscript end cell row cell negative a subscript 1 end subscript c subscript 2 end subscript end cell cell negative a subscript 2 end subscript b subscript 1 end subscript end cell end table close vertical bar plus open vertical bar table row cell negative a subscript 3 end subscript c subscript 1 end subscript end cell cell negative a subscript 1 end subscript b subscript 3 end subscript end cell row cell a subscript 2 end subscript c subscript 1 end subscript end cell cell a subscript 1 end subscript b subscript 2 end subscript end cell end table close vertical bar plus open vertical bar table row cell negative a subscript 3 end subscript c subscript 1 end subscript end cell cell a subscript 3 end subscript b subscript 1 end subscript end cell row cell a subscript 2 end subscript c subscript 1 end subscript end cell cell negative a subscript 2 end subscript b subscript 1 end subscript end cell end table close vertical bar
    equals a subscript 1 end subscript superscript 2 end superscript open vertical bar table row cell c subscript 3 end subscript end cell cell negative b subscript 3 end subscript end cell row cell negative c subscript 2 end subscript end cell cell b subscript 2 end subscript end cell end table close vertical bar plus a subscript 1 end subscript b subscript 1 end subscript open vertical bar table row cell c subscript 3 end subscript end cell cell a subscript 3 end subscript end cell row cell negative c subscript 2 end subscript end cell cell negative a subscript 2 end subscript end cell end table close vertical bar plus a subscript 1 end subscript c subscript 1 end subscript open vertical bar table row cell negative a subscript 3 end subscript end cell cell negative b subscript 3 end subscript end cell row cell a subscript 2 end subscript end cell cell b subscript 2 end subscript end cell end table close vertical bar plus b subscript 1 end subscript c subscript 1 end subscript open vertical bar table row cell negative a subscript 3 end subscript end cell cell a subscript 3 end subscript end cell row cell a subscript 2 end subscript end cell cell negative a subscript 2 end subscript end cell end table close vertical bar
    equals a subscript 1 end subscript left curly bracket a subscript 1 end subscript open parentheses b subscript 2 end subscript c subscript 3 end subscript minus b subscript 3 end subscript c subscript 2 end subscript close parentheses minus b subscript 1 end subscript open parentheses a subscript 2 end subscript c subscript 3 end subscript minus a subscript 3 end subscript c subscript 2 end subscript close parentheses plus c subscript 1 end subscript left parenthesis a subscript 2 end subscript b subscript 3 end subscript minus a subscript 3 end subscript b subscript 2 end subscript right parenthesis right curly bracket
    equals a subscript 1 end subscript open vertical bar table row cell a subscript 1 end subscript end cell cell b subscript 1 end subscript end cell cell c subscript 1 end subscript end cell row cell a subscript 2 end subscript end cell cell b subscript 2 end subscript end cell cell c subscript 2 end subscript end cell row cell a subscript 3 end subscript end cell cell b subscript 3 end subscript end cell cell c subscript 3 end subscript end cell end table close vertical bar equals a subscript 1 end subscript increment

    Related Questions to study

    General
    Maths-

    Let stack a with rightwards arrow on top be a unit vector perpendicular to unit vectors stack b with rightwards arrow on top a n d stack c with rightwards arrow on top inclined at an angle a, then stack b with rightwards arrow on top cross times stack c with rightwards arrow on top is

    Let stack a with rightwards arrow on top be a unit vector perpendicular to unit vectors stack b with rightwards arrow on top a n d stack c with rightwards arrow on top inclined at an angle a, then stack b with rightwards arrow on top cross times stack c with rightwards arrow on top is

    Maths-General
    General
    Maths-

    Let stack a with rightwards arrow on top comma short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow stack b with rightwards arrow on top short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow a n d short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow stack c with rightwards arrow on top be three non-coplanar vectors and stack d with rightwards arrow on top be a non-zero vector which is perpendicular to open parentheses stack a with rightwards arrow on top plus stack b with rightwards arrow on top plus stack c with rightwards arrow on top close parentheses and is represented as stack d with rightwards arrow on top equals x open parentheses stack a with rightwards arrow on top cross times stack b with rightwards arrow on top close parentheses plus y open parentheses stack b with rightwards arrow on top cross times stack c with rightwards arrow on top close parentheses plus z open parentheses stack c with rightwards arrow on top cross times stack a with rightwards arrow on top close parentheses. Then

    Let stack a with rightwards arrow on top comma short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow stack b with rightwards arrow on top short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow a n d short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow stack c with rightwards arrow on top be three non-coplanar vectors and stack d with rightwards arrow on top be a non-zero vector which is perpendicular to open parentheses stack a with rightwards arrow on top plus stack b with rightwards arrow on top plus stack c with rightwards arrow on top close parentheses and is represented as stack d with rightwards arrow on top equals x open parentheses stack a with rightwards arrow on top cross times stack b with rightwards arrow on top close parentheses plus y open parentheses stack b with rightwards arrow on top cross times stack c with rightwards arrow on top close parentheses plus z open parentheses stack c with rightwards arrow on top cross times stack a with rightwards arrow on top close parentheses. Then

    Maths-General
    General
    Maths-

    Let OPQR is a tetrahedron such that O is origin and stack p with rightwards arrow on top comma short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow stack q with rightwards arrow on top comma short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow stack r with rightwards arrow on topare position vectors of P, Q, R respectively and a is the angle which OP makes with face PQR then

    Hence required angle is 2.

    Let OPQR is a tetrahedron such that O is origin and stack p with rightwards arrow on top comma short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow stack q with rightwards arrow on top comma short rightwards arrow over leftwards arrow short rightwards arrow over leftwards arrow stack r with rightwards arrow on topare position vectors of P, Q, R respectively and a is the angle which OP makes with face PQR then

    Maths-General

    Hence required angle is 2.

    parallel
    General
    Chemistry-

    On strong heating Mgcl2  6H2 Othe product obtained is

    On strong heating Mgcl2  6H2 Othe product obtained is

    Chemistry-General
    General
    Chemistry-

    Which one of the following hydroxide is insoluble in water?

    Which one of the following hydroxide is insoluble in water?

    Chemistry-General
    General
    Chemistry-

    Which is the incorrect statement?

    Which is the incorrect statement?

    Chemistry-General
    parallel
    General
    Chemistry-

    Which salt can be used to identify coloured cation?

    Which salt can be used to identify coloured cation?

    Chemistry-General
    General
    Chemistry-

    Which will give N subscript 2 end subscript O on heating?

    Which will give N subscript 2 end subscript O on heating?

    Chemistry-General
    General
    Chemistry-

    Some of alkali metal salts are coloured. N a subscript 2 end subscript C r O subscript 4 end subscript minusyellow, K M n O subscript 4 end subscript minuspink, K subscript 2 end subscript M n O subscript 4 end subscript minusgreen. It is due to

    Some of alkali metal salts are coloured. N a subscript 2 end subscript C r O subscript 4 end subscript minusyellow, K M n O subscript 4 end subscript minuspink, K subscript 2 end subscript M n O subscript 4 end subscript minusgreen. It is due to

    Chemistry-General
    parallel
    General
    Maths-

    The equation of the hyperbola whose foci are (6, 4) and (–4, 4) and eccentricity 2 is given by

    The equation of the hyperbola whose foci are (6, 4) and (–4, 4) and eccentricity 2 is given by

    Maths-General
    General
    Chemistry-

    Mg and Li are similar in their properties due to

    Mg and Li are similar in their properties due to

    Chemistry-General
    General
    Chemistry-

    When an electron makes a transition from left parenthesis n plus 1 right parenthesis state to n state, the frequency of emitted radiations is related to n according to left parenthesis n much greater-than 1 right parenthesis

    When an electron makes a transition from left parenthesis n plus 1 right parenthesis state to n state, the frequency of emitted radiations is related to n according to left parenthesis n much greater-than 1 right parenthesis

    Chemistry-General
    parallel
    General
    Chemistry-

    The binding energy of an element is 64 Mev. If BE/nucleon is 6.4, then the number of nucleons are

    The binding energy of an element is 64 Mev. If BE/nucleon is 6.4, then the number of nucleons are

    Chemistry-General
    General
    Chemistry-

    The ionization potential hydrogen atom is 13.6 blank e V. The energy required to remove an electron in the n equals 2 state of the hydrogen atom is

    The ionization potential hydrogen atom is 13.6 blank e V. The energy required to remove an electron in the n equals 2 state of the hydrogen atom is

    Chemistry-General
    General
    Chemistry-

    In nuclear reaction, blank subscript 3 end subscript superscript 7 end superscript L i plus blank subscript 1 end subscript superscript 1 end superscript H rightwards arrow 2 blank subscript 2 end subscript superscript 4 end superscript H e The mass loss is nearly 0.02 amu. Hence, the energy released (in units of million kcal/mol) in the process is approximately

    In nuclear reaction, blank subscript 3 end subscript superscript 7 end superscript L i plus blank subscript 1 end subscript superscript 1 end superscript H rightwards arrow 2 blank subscript 2 end subscript superscript 4 end superscript H e The mass loss is nearly 0.02 amu. Hence, the energy released (in units of million kcal/mol) in the process is approximately

    Chemistry-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.