Question
For the primitive integral equation then is
- 3
- 2
- 1
- 5
Hint:
We are given the primitive intergral equation. We are given the conditions of it. We are asked to find the value of equation when x = - 3. We will rearrange and integrate the equation. Then we will substitute the equation.
The correct answer is: 3
The given equation is ydx + y2dy = xdx
The conditions are as follows:
y > 0
y = y(x)
y(1) = 1
We have to find y(-3)
We will find the value of c now. We will use the conditions given to us.
The equation becomes
It means (3 - y) = 0 or (y + 1) = 0
3 - y = 0
y = 3
y + 1 = 0
y = - 1
But, we have condition that y > 0
So, y ≠ 1.
Therefore, y(-3) = 3
The right option is 3.
For such questions, we should know different method of differentiation and integration.
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