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Question

he value of $cos invisible function application fraction numerator pi over denominator 7 end fraction plus cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 3 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 5 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 6 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 7 pi over denominator 7 end fraction$ is

1
$- 1$
0
None of these

The correct answer is: $negative 1$

$W e blank h a v e cos invisible function application fraction numerator pi over denominator 7 end fraction plus cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 3 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 5 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 6 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 7 pi over denominator 7 end fraction blank$
$equals open parentheses cos invisible function application fraction numerator pi over denominator 7 end fraction plus cos invisible function application fraction numerator 6 pi over denominator 7 end fraction close parentheses plus open parentheses cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 5 pi over denominator 7 end fraction close parentheses plus open parentheses cos invisible function application fraction numerator 3 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction close parentheses plus cos invisible function application pi$
$equals open parentheses cos invisible function application fraction numerator pi over denominator 7 end fraction minus cos invisible function application fraction numerator pi over denominator 7 end fraction close parentheses plus open parentheses cos invisible function application fraction numerator 2 pi over denominator 7 end fraction minus cos invisible function application fraction numerator 2 pi over denominator 7 end fraction close parentheses plus open parentheses cos invisible function application fraction numerator 3 pi over denominator 7 end fraction minus cos invisible function application fraction numerator 3 pi over denominator 7 end fraction close parentheses plus cos invisible function application pi$
$equals cos invisible function application pi equals negative 1$

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f $alpha plus beta equals pi divided by 2$ and $beta plus gamma equals alpha comma$ then $tan invisible function application alpha blank e q u a l s$

he smallest $plus v e blank x$ satisfying the equation $log subscript cos invisible function application x end subscript invisible function application sin invisible function application x plus log subscript sin invisible function application x end subscript invisible function application cos invisible function application x equals 2$ is

he smallest $plus v e blank x$ satisfying the equation $log subscript cos invisible function application x end subscript invisible function application sin invisible function application x plus log subscript sin invisible function application x end subscript invisible function application cos invisible function application x equals 2$ is

f $log subscript 4 end subscript invisible function application 5 equals a blank a n d log subscript 5 end subscript invisible function application 6 equals b comma$ then $log subscript 3 end subscript invisible function application 2$ is equal to

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f in $increment A B C comma blank 8 R to the power of 2 end exponent equals a to the power of 2 end exponent plus b to the power of 2 end exponent plus c to the power of 2 end exponent comma$ then the triangle $A B C$ is

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parallel

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parallel

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parallel

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