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If left parenthesis fraction numerator 2 plus blank s i n blank x over denominator 1 plus y end fraction right parenthesis fraction numerator d y over denominator d x end fraction equals negative blank c o s blank x comma y left parenthesis 0 right parenthesis equals 1, then y left parenthesis fraction numerator pi over denominator 2 end fraction right parenthesis equals

  1. 1    
  2. fraction numerator 1 over denominator 2 end fraction    
  3. fraction numerator 1 over denominator 3 end fraction    
  4. fraction numerator 1 over denominator 4 end fraction    

The correct answer is: fraction numerator 1 over denominator 3 end fraction


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