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Maths-

General

Easy

Question

The ratio in which the area bounded by the curves $y to the power of 2 end exponent equals x$ and $x to the power of 2 end exponent equals y i s$ divided by the Iine $x equals fraction numerator 1 over denominator 2 end fraction$ is

$\frac{4 \sqrt{2} - 1}{9 - 4 \sqrt{2}}$
$\frac{3 \sqrt{2} + 3}{9 - 4 \sqrt{2}}$
$\frac{\sqrt{2} - 1}{\sqrt{3} - 1}$
$\frac{2 \sqrt{2} - 1}{3 \sqrt{3} - 1}$

The correct answer is: $fraction numerator 4 square root of 2 minus 1 over denominator 9 minus 4 square root of 2 end fraction$

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