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Maths-

General

Easy

Question

The general solution of $y to the power of 2 end exponent d x plus left parenthesis x to the power of 2 end exponent minus x y plus y to the power of 2 end exponent right parenthesis d y equals 0$ is

${t a n}^{- 1} (\frac{x}{y}) + I o g y + c = 0$
$2 {t a n}^{- 1} (\frac{x}{y}) +$ Iogx $+ c = 0$
$| (\sqrt{x^{2} + y^{2}}) + | \circ g y + c = 0$
${s i n h}^{- 1} (\frac{x}{y}) + I o g y + c = 0$

The correct answer is: $t a n to the power of negative 1 end exponent left parenthesis fraction numerator x over denominator y end fraction right parenthesis plus I o g y plus c equals 0$

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