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Question

If $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 comma blank 6 close curly brackets comma$ then how many subsets of $A$ contain the elements $2 comma blank 3$ and $5 ?$

4
8
16
32

The correct answer is: 8

The number of subsets of $A$ containing 2, 3 and 5 is same as the number of subsets of set $left curly bracket 1 comma blank 4 comma blank 6 right curly bracket$ which is equal to $2 to the power of 3 end exponent equals 8$

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