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Question

If $A equals open curly brackets 1 comma blank 2 comma blank 3 close curly brackets comma blank B open curly brackets 3 comma blank 4 close curly brackets comma blank C left curly bracket 4 comma blank 5 comma blank 6 right curly bracket$ . Then, $A union left parenthesis B intersection C right parenthesis$ is

{1, 2}
{ $ϕ$ }
{4, 5}
{1, 2, 3, 4}

The correct answer is: {1, 2, 3, 4}

$B intersection C equals open curly brackets 4 close curly brackets.$
$therefore A union open parentheses B intersection C close parentheses equals left curly bracket 1 comma blank 2 comma blank 3 comma blank 4 right curly bracket$

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Set builder form of the relation
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