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Question

If a circle of radius r is concentric with ellipse fraction numerator x to the power of 2 end exponent over denominator a to the power of 2 end exponent end fraction plus fraction numerator y to the power of 2 end exponent over denominator b to the power of 2 end exponent end fraction equals 1, then common tangent is inclined to the major axis at an angle-

  1. tan invisible function application root index negative 1 of fraction numerator r squared minus b squared over denominator a squared minus r squared end fraction end root  
  2. tan to the power of negative 1 end exponent invisible function application square root of fraction numerator r squared minus b squared over denominator r squared minus a squared end fraction end root  
  3. tan invisible function application root index negative 1 of fraction numerator a squared minus r squared over denominator r squared minus b squared end fraction end root    
  4. None of these    

hintHint:

find the equations of tangents to the circle and ellipse. apply the condition required to find the value of theta.

The correct answer is: tan invisible function application root index negative 1 of fraction numerator r squared minus b squared over denominator a squared minus r squared end fraction end root


    tan invisible function application root index negative 1 of fraction numerator r squared minus b squared over denominator a squared minus r squared end fraction end root

    Equation of tangent to the circle : x cos t + y sin t = r
    Equation of tangent to the ellipse :
    y= mx + √(a2m2+b2)

    for the line to be a tangent to the circle, the perpendicular has to be equal to r
    => √(a2m2+b2)/ √(m2+1) = r
    => a2m2+b2 = m2r2 + r2
    m= √(r2-b2)/a2-r2 = tan Ѳ

    Ѳ =  tan -1(√(r2-b2)/a2-r2 )

    the perpendicular distance from the tangent to the center of the circle is equal to the radius of the circle.

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