Maths-
General
Easy

Question

If cos invisible function application B cos invisible function application C plus sin invisible function application B sin invisible function application C sin to the power of 2 end exponent invisible function application A equals 1 comma then triangle A B C is

  1. Isosceles and right angled  
  2. Equilateral  
  3. Isosceles whose equal angles are greater than pi divided by 4  
  4. None   

The correct answer is: Isosceles and right angled


    Given, cos invisible function application B cos invisible function application C plus sin invisible function application B sin invisible function application C sin to the power of 2 end exponent invisible function application A equals 1 (i)
    Now, we know that sin to the power of 2 end exponent invisible function application A less or equal than 1 (ii)
    Also, sin invisible function application B and sin invisible function application C are positive
    rightwards double arrow sin invisible function application B sin invisible function application C sin to the power of 2 end exponent invisible function application A less or equal than sin invisible function application B sin invisible function application C (iii)
    rightwards double arrow 1 minus cos invisible function application B cos invisible function application C less or equal than sin invisible function application B sin invisible function application C, [by using Eq.(i) ]
    rightwards double arrow cos invisible function application open parentheses B minus C close parentheses greater or equal than 1 blank rightwards double arrow cos invisible function application open parentheses B minus C close parentheses equals 1 blank rightwards double arrow B minus C equals 0 blank rightwards double arrow B equals C
    Also, sin to the power of 2 end exponent invisible function application A equals 1 comma blank i. e. comma blank A equals pi divided by 2. Hence, the triangle is right-angled isosceles

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