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Maths-

General

Easy

Question

If $cos invisible function application theta equals 1 half open parentheses a plus 1 over a close parentheses$ then $cos invisible function application 3 theta$ in terms of ‘a’ =

$\frac{1}{4} (a^{3} + \frac{1}{a^{3}})$
$^{4 (a^{3} + \frac{1}{a^{3}})}$
$\frac{1}{2} (a^{3} + \frac{1}{a^{3}})$
none

The correct answer is: none

Use cos 3q = 4 cos3 q – 3 cosq.

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