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If x enotes the rounded off value of x left parenthesis 3.4 equals 3 comma 3.5 equals 4 comma 3.8 equals text  4etc  end text right parenthesis and the area bounded by the two curves defined by y = vertical line x minus x with not stretchy bar on top vertical line and y equals lambda sin invisible function application left parenthesis pi x right parenthesis comma lambda 1. In the interval 0 x 1 is equal to 2 square units, The value of the constant is

  1. fraction numerator 7 pi over denominator 8 end fraction    
  2. fraction numerator 5 pi over denominator 8 end fraction    
  3. fraction numerator 9 pi over denominator 8 end fraction    
  4. none of these    

The correct answer is: fraction numerator 9 pi over denominator 8 end fraction


    0 < 0.5 = 0 y = |x 0| = x
    0.5 x 1, = 1 y = |x 1| = 1 x

    given that stretchy integral subscript 0 end subscript superscript 1 end superscript   lambda s i n invisible function application left parenthesis pi x right parenthesis minus fraction numerator 1 over denominator 2 end fractionx(1) (0.5)
    = 2 = 2 + =
    open fraction numerator lambda c o s invisible function application left parenthesis pi x right parenthesis over denominator pi end fraction close vertical bar subscript b end subscript superscript 1 end superscript
    

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