Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If $R$ be a relation $less than$ from $A equals left curly bracket 12 comma 34 right curly bracket$ to $B equals open curly brackets 13 comma 5 close curly brackets blank i. e. blank open parentheses a comma b close parentheses element of R left right double arrow a less than b comma$ then $R blank o blank R to the power of negative 1 end exponent$ is

$\{(1,3), (1,5), (2,3), (2,5), (3,5), (4,5)\}$
${(3,1), (5,1), (3,2), (5,2), (5,3), (5,4)}$
${(3,3), (3,5), (5,3), (5,5)}$
${(3,3), (3,4), (4,5)}$

The correct answer is: $left curly bracket open parentheses 33 close parentheses comma open parentheses 35 close parentheses comma open parentheses 53 close parentheses comma left parenthesis 55 right parenthesis right curly bracket$

We have,
$R equals left curly bracket open parentheses 13 close parentheses comma open parentheses 15 close parentheses comma open parentheses 23 close parentheses comma open parentheses 25 close parentheses comma open parentheses 35 close parentheses comma left parenthesis 45 right parenthesis right curly bracket$
$rightwards double arrow R to the power of negative 1 end exponent equals left curly bracket open parentheses 31 close parentheses comma open parentheses 51 close parentheses comma open parentheses 32 close parentheses comma open parentheses 52 close parentheses comma open parentheses 53 close parentheses comma left parenthesis 54 right parenthesis right curly bracket$
Hence, $R blank o blank R to the power of negative 1 end exponent equals left curly bracket open parentheses 33 close parentheses comma open parentheses 35 close parentheses comma open parentheses 53 close parentheses comma left parenthesis 55 right parenthesis right curly bracket$

Related Questions to study

Let $R$ be a relation on the set $N$ be defined by $open curly brackets open parentheses x comma y close parentheses vertical line x comma y element of N comma 2 blank x plus y equals 41 close curly brackets.$ Then, $R$ is

Let $R$ be a relation on the set $N$ be defined by $open curly brackets open parentheses x comma y close parentheses vertical line x comma y element of N comma 2 blank x plus y equals 41 close curly brackets.$ Then, $R$ is

If $A equals open curly brackets 1 comma blank 2 comma blank 3 close curly brackets comma$ then the relation $R equals left curly bracket open parentheses 11 close parentheses comma open parentheses 22 close parentheses comma open parentheses 31 close parentheses comma left parenthesis 13 right parenthesis right curly bracket$ is

If $A equals open curly brackets 1 comma blank 2 comma blank 3 close curly brackets comma$ then the relation $R equals left curly bracket open parentheses 11 close parentheses comma open parentheses 22 close parentheses comma open parentheses 31 close parentheses comma left parenthesis 13 right parenthesis right curly bracket$ is

Let $R$ be a relation defined on $S comma$ the set of squares on a chess board such that $x R y$ iff $x$ and $y$ share a common side. Then, which of the following is false for $R ?$

Let $R$ be a relation defined on $S comma$ the set of squares on a chess board such that $x R y$ iff $x$ and $y$ share a common side. Then, which of the following is false for $R ?$

parallel

If $A equals open curly brackets 1 comma blank 2 comma blank 3 close curly brackets comma blank B equals left curly bracket a comma blank b right curly bracket$ , then $A cross times B$ mapped $A$ to $B$ is

If $A equals open curly brackets 1 comma blank 2 comma blank 3 close curly brackets comma blank B equals left curly bracket a comma blank b right curly bracket$ , then $A cross times B$ mapped $A$ to $B$ is

In a town of $10000$ families $blank$ it was found that 40% families buy newspaper $A comma 20 percent sign$ families buy newspaper $B$ and 10% families buy newspaper $C comma blank 5 percent sign$ families buy $A$ and $B comma$ 3% buy $B$ and $C$ and 4% buy $A$ and $C.$ If 2% families buy all the three newspapers, then the number of families which buy $A$ only is

In a town of $10000$ families $blank$ it was found that 40% families buy newspaper $A comma 20 percent sign$ families buy newspaper $B$ and 10% families buy newspaper $C comma blank 5 percent sign$ families buy $A$ and $B comma$ 3% buy $B$ and $C$ and 4% buy $A$ and $C.$ If 2% families buy all the three newspapers, then the number of families which buy $A$ only is

f $c o s e c blank theta minus cot invisible function application theta equals q comma blank$ then the value of $c o s e c blank theta$ is

f $c o s e c blank theta minus cot invisible function application theta equals q comma blank$ then the value of $c o s e c blank theta$ is

parallel

n triangle $A B C comma blank$ if $blank r subscript 1 end subscript equals 2 r subscript 2 end subscript equals 3 r subscript 3 end subscript comma$ then $blank a colon b$ is equal to

n triangle $A B C comma blank$ if $blank r subscript 1 end subscript equals 2 r subscript 2 end subscript equals 3 r subscript 3 end subscript comma$ then $blank a colon b$ is equal to

f $c o s e c blank theta minus cot invisible function application theta equals q comma blank$ then the value of $c o s e c blank theta$ is

f $c o s e c blank theta minus cot invisible function application theta equals q comma blank$ then the value of $c o s e c blank theta$ is

n triangle $A B C comma blank$ if $blank r subscript 1 end subscript equals 2 r subscript 2 end subscript equals 3 r subscript 3 end subscript comma$ then $blank a colon b$ is equal to

n triangle $A B C comma blank$ if $blank r subscript 1 end subscript equals 2 r subscript 2 end subscript equals 3 r subscript 3 end subscript comma$ then $blank a colon b$ is equal to

parallel

f $a comma blank b blank$ and $blank A$ are given in a triangle and $c subscript 1 end subscript comma blank c subscript 2 end subscript$ are the possible values of the third side, then $c subscript 1 end subscript superscript 2 end superscript plus c subscript 2 end subscript superscript 2 end superscript minus 2 c subscript 1 end subscript c subscript 2 end subscript cos invisible function application A equals$ is equal to

f $a comma blank b blank$ and $blank A$ are given in a triangle and $c subscript 1 end subscript comma blank c subscript 2 end subscript$ are the possible values of the third side, then $c subscript 1 end subscript superscript 2 end superscript plus c subscript 2 end subscript superscript 2 end superscript minus 2 c subscript 1 end subscript c subscript 2 end subscript cos invisible function application A equals$ is equal to

he equation $sin invisible function application x open parentheses sin invisible function application x plus cos invisible function application x close parentheses equals k$ has real solutions if and only if $k$ is a real number such that

he equation $sin invisible function application x open parentheses sin invisible function application x plus cos invisible function application x close parentheses equals k$ has real solutions if and only if $k$ is a real number such that

he equation $open parentheses cos invisible function application p minus 1 close parentheses x to the power of 2 end exponent plus open parentheses cos invisible function application p close parentheses x plus sin invisible function application p equals 0$ in the variable $x$ has real roots. Then $p$ can take any value in the interval

he equation $open parentheses cos invisible function application p minus 1 close parentheses x to the power of 2 end exponent plus open parentheses cos invisible function application p close parentheses x plus sin invisible function application p equals 0$ in the variable $x$ has real roots. Then $p$ can take any value in the interval

parallel

he value of expression $square root of 3 c o s e c blank 20 degree minus sec invisible function application 20 degree$ is equal to

he value of expression $square root of 3 c o s e c blank 20 degree minus sec invisible function application 20 degree$ is equal to

$f cos invisible function application x equals fraction numerator 2 cos invisible function application y minus 1 over denominator 2 minus cos invisible function application y end fraction comma blank w h e r e blank x comma blank y element of open parentheses 0 comma blank pi close parentheses comma blank t h e n tan invisible function application fraction numerator x over denominator 2 end fraction cot invisible function application fraction numerator y over denominator 2 end fraction blank i s blank e q u a l blank t o$

$f cos invisible function application x equals fraction numerator 2 cos invisible function application y minus 1 over denominator 2 minus cos invisible function application y end fraction comma blank w h e r e blank x comma blank y element of open parentheses 0 comma blank pi close parentheses comma blank t h e n tan invisible function application fraction numerator x over denominator 2 end fraction cot invisible function application fraction numerator y over denominator 2 end fraction blank i s blank e q u a l blank t o$

he value of $cos invisible function application fraction numerator pi over denominator 7 end fraction plus cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 3 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 5 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 6 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 7 pi over denominator 7 end fraction$ is

he value of $cos invisible function application fraction numerator pi over denominator 7 end fraction plus cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 3 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 5 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 6 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 7 pi over denominator 7 end fraction$ is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.