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Question

n triangle $A B C comma blank$ if $blank r subscript 1 end subscript equals 2 r subscript 2 end subscript equals 3 r subscript 3 end subscript comma$ then $blank a colon b$ is equal to

$\frac{5}{4}$
$\frac{4}{5}$
$\frac{7}{4}$
$\frac{4}{7}$

The correct answer is: $fraction numerator 5 over denominator 4 end fraction$

$r subscript 1 end subscript equals 2 r subscript 2 end subscript equals 3 r subscript 3 end subscript$
$rightwards double arrow fraction numerator increment over denominator s minus a end fraction equals 2 fraction numerator increment over denominator s minus b end fraction equals 3 fraction numerator increment over denominator s minus c end fraction$
$rightwards double arrow fraction numerator 1 over denominator s minus a end fraction equals fraction numerator 2 over denominator s minus b end fraction equals fraction numerator 3 over denominator s minus c end fraction equals k blank open parentheses s a y close parentheses$
$rightwards double arrow s minus a equals fraction numerator 1 over denominator k end fraction comma blank s minus b equals fraction numerator 2 over denominator k end fraction blank a n d blank s minus c equals fraction numerator 3 over denominator k end fraction$
Adding, we get $blank 3 s minus open parentheses a plus b plus c close parentheses equals fraction numerator 6 over denominator k end fraction blank rightwards double arrow s equals fraction numerator 6 over denominator k end fraction blank rightwards double arrow a equals fraction numerator 5 over denominator k end fraction blank$ and $blank b equals fraction numerator 4 over denominator k end fraction blank rightwards double arrow fraction numerator a over denominator b end fraction equals fraction numerator 5 over denominator 4 end fraction$

Related Questions to study

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f $c o s e c blank theta minus cot invisible function application theta equals q comma blank$ then the value of $c o s e c blank theta$ is

n triangle $A B C comma blank$ if $blank r subscript 1 end subscript equals 2 r subscript 2 end subscript equals 3 r subscript 3 end subscript comma$ then $blank a colon b$ is equal to

n triangle $A B C comma blank$ if $blank r subscript 1 end subscript equals 2 r subscript 2 end subscript equals 3 r subscript 3 end subscript comma$ then $blank a colon b$ is equal to

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f $a comma blank b blank$ and $blank A$ are given in a triangle and $c subscript 1 end subscript comma blank c subscript 2 end subscript$ are the possible values of the third side, then $c subscript 1 end subscript superscript 2 end superscript plus c subscript 2 end subscript superscript 2 end superscript minus 2 c subscript 1 end subscript c subscript 2 end subscript cos invisible function application A equals$ is equal to

parallel

he equation $sin invisible function application x open parentheses sin invisible function application x plus cos invisible function application x close parentheses equals k$ has real solutions if and only if $k$ is a real number such that

he equation $sin invisible function application x open parentheses sin invisible function application x plus cos invisible function application x close parentheses equals k$ has real solutions if and only if $k$ is a real number such that

he equation $open parentheses cos invisible function application p minus 1 close parentheses x to the power of 2 end exponent plus open parentheses cos invisible function application p close parentheses x plus sin invisible function application p equals 0$ in the variable $x$ has real roots. Then $p$ can take any value in the interval

he equation $open parentheses cos invisible function application p minus 1 close parentheses x to the power of 2 end exponent plus open parentheses cos invisible function application p close parentheses x plus sin invisible function application p equals 0$ in the variable $x$ has real roots. Then $p$ can take any value in the interval

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he value of expression $square root of 3 c o s e c blank 20 degree minus sec invisible function application 20 degree$ is equal to

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$f cos invisible function application x equals fraction numerator 2 cos invisible function application y minus 1 over denominator 2 minus cos invisible function application y end fraction comma blank w h e r e blank x comma blank y element of open parentheses 0 comma blank pi close parentheses comma blank t h e n tan invisible function application fraction numerator x over denominator 2 end fraction cot invisible function application fraction numerator y over denominator 2 end fraction blank i s blank e q u a l blank t o$

$f cos invisible function application x equals fraction numerator 2 cos invisible function application y minus 1 over denominator 2 minus cos invisible function application y end fraction comma blank w h e r e blank x comma blank y element of open parentheses 0 comma blank pi close parentheses comma blank t h e n tan invisible function application fraction numerator x over denominator 2 end fraction cot invisible function application fraction numerator y over denominator 2 end fraction blank i s blank e q u a l blank t o$

he value of $cos invisible function application fraction numerator pi over denominator 7 end fraction plus cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 3 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 5 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 6 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 7 pi over denominator 7 end fraction$ is

he value of $cos invisible function application fraction numerator pi over denominator 7 end fraction plus cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 3 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 5 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 6 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 7 pi over denominator 7 end fraction$ is

f $alpha plus beta equals pi divided by 2$ and $beta plus gamma equals alpha comma$ then $tan invisible function application alpha blank e q u a l s$

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parallel

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he smallest $plus v e blank x$ satisfying the equation $log subscript cos invisible function application x end subscript invisible function application sin invisible function application x plus log subscript sin invisible function application x end subscript invisible function application cos invisible function application x equals 2$ is

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parallel

The total number of solutions of $open vertical bar cot invisible function application x close vertical bar equals cot invisible function application x plus fraction numerator 1 over denominator sin invisible function application x end fraction comma blank x element of open square brackets 0 comma blank 3 pi close square brackets$ is equal to

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$fraction numerator sin invisible function application 3 theta plus sin invisible function application 5 theta plus sin invisible function application 7 theta plus sin invisible function application 9 theta over denominator cos invisible function application 3 theta plus cos invisible function application 5 theta plus cos invisible function application 7 theta plus cos invisible function application 9 theta end fraction blank i s blank e q u a l blank t o$

parallel

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