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Maths-

General

Easy

Question

If $sin invisible function application x plus c o s e c blank x equals 2 comma$ then $sin to the power of n end exponent invisible function application x plus blank c o s e c to the power of n end exponent x$ is equal to

2
$2^{n}$
$2^{n - 1}$
$2^{n - 2}$

The correct answer is: 2

$sin invisible function application x plus blank c o s e c blank x equals 2$
$rightwards double arrow open parentheses sin invisible function application x minus 1 close parentheses to the power of 2 end exponent equals 0$
$rightwards double arrow sin invisible function application x equals 1$
$rightwards double arrow sin to the power of n end exponent invisible function application x plus c o s e c to the power of n end exponent x equals 1 plus 1 equals 2$

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