Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics-

General

Easy

Question

If in a coil rate of change of area is $fraction numerator 5 blank m e t r e to the power of 2 end exponent over denominator m i l l i blank s e c o n d end fraction$ , current becomes $1 blank a m p$ form $2 blank a m p$ in $2 cross times 10 to the power of negative 3 end exponent s e c$ magnetic field is $1 blank t e s l a$ , then self inductance of the coil is

$2 H$
$5 H$
$20 H$
$10 H$

The correct answer is: $10 blank H$

$e equals B. fraction numerator d A over denominator d t end fraction equals L fraction numerator d i over denominator d t end fraction rightwards double arrow 1 cross times fraction numerator 5 over denominator 10 to the power of negative 3 end exponent end fraction equals L cross times fraction numerator left parenthesis 2 minus 1 right parenthesis over denominator 2 cross times 10 to the power of negative 3 end exponent end fraction rightwards double arrow L equals 10 H$

Related Questions to study

One conducting U-tube can slide inside another as shown in figure, maintaining electrical contacts between the tubes. The magnetic field B is perpendicular to the plane of the figure. If each tube moves towards the other at a constant speed $v$ , then the emf induced in the circuit in terms of $B comma blank l a n d blank v comma blank w h e r e blank l$ is the width of each tube, will be

One conducting U-tube can slide inside another as shown in figure, maintaining electrical contacts between the tubes. The magnetic field B is perpendicular to the plane of the figure. If each tube moves towards the other at a constant speed $v$ , then the emf induced in the circuit in terms of $B comma blank l a n d blank v comma blank w h e r e blank l$ is the width of each tube, will be

Physics-General

Self-inductance of a coil is $50 blank m H$ . A current of $1 blank A$ passing through the coil reduces to zero at steady rate in $0.1 blank s e c$ ., the self-induced $e m f$ is

Self-inductance of a coil is $50 blank m H$ . A current of $1 blank A$ passing through the coil reduces to zero at steady rate in $0.1 blank s e c$ ., the self-induced $e m f$ is

Physics-General

A magnetic field of $2 cross times 10 to the power of negative 2 end exponent T$ acts at right angles to a coil of area $100 blank c m to the power of 2 end exponent$ with 50 turns. The average emf induced in the coil is $0.1 blank V$ , when it is removed from the field in time $T$ . The value of $t$ is

A magnetic field of $2 cross times 10 to the power of negative 2 end exponent T$ acts at right angles to a coil of area $100 blank c m to the power of 2 end exponent$ with 50 turns. The average emf induced in the coil is $0.1 blank V$ , when it is removed from the field in time $T$ . The value of $t$ is

Physics-General

parallel

The variation of induced emf $left parenthesis epsilon right parenthesis$ with time (t ) in a coil if a short bar magnet is moved along its axis with a constant velocity is best represented as

The variation of induced emf $left parenthesis epsilon right parenthesis$ with time (t ) in a coil if a short bar magnet is moved along its axis with a constant velocity is best represented as

Physics-General

A copper ring having a cut such as not to form a complete loop is held horizontally ad a bar magnet is dropped through the ring with its length along the axis of the ring, figure. The acceleration of the falling magnet is

A copper ring having a cut such as not to form a complete loop is held horizontally ad a bar magnet is dropped through the ring with its length along the axis of the ring, figure. The acceleration of the falling magnet is

Physics-General

For previous objective, which of the following graphs is correct

For previous objective, which of the following graphs is correct

Physics-General

parallel

If in a triangle $comma blank open parentheses 1 minus fraction numerator r subscript 1 end subscript over denominator r subscript 2 end subscript end fraction close parentheses open parentheses 1 minus fraction numerator r subscript 1 end subscript over denominator r subscript 3 end subscript end fraction close parentheses equals 2 comma blank$ then the triangle is

If in a triangle $comma blank open parentheses 1 minus fraction numerator r subscript 1 end subscript over denominator r subscript 2 end subscript end fraction close parentheses open parentheses 1 minus fraction numerator r subscript 1 end subscript over denominator r subscript 3 end subscript end fraction close parentheses equals 2 comma blank$ then the triangle is

$I f sin to the power of negative 1 end exponent invisible function application a plus sin to the power of negative 1 end exponent invisible function application b plus sin to the power of negative 1 end exponent invisible function application c equals pi$ , then $blank a square root of 1 minus a to the power of 2 end exponent end root plus b square root of 1 minus b to the power of 2 end exponent end root plus c square root of 1 minus c to the power of 2 end exponent end root$ is equal to

$I f sin to the power of negative 1 end exponent invisible function application a plus sin to the power of negative 1 end exponent invisible function application b plus sin to the power of negative 1 end exponent invisible function application c equals pi$ , then $blank a square root of 1 minus a to the power of 2 end exponent end root plus b square root of 1 minus b to the power of 2 end exponent end root plus c square root of 1 minus c to the power of 2 end exponent end root$ is equal to

The side of triangle $A B C$ are in A.P. (order being $a comma blank b comma blank c$ ) and satisfy $fraction numerator 2 factorial over denominator 1 factorial 9 factorial end fraction plus fraction numerator 2 factorial over denominator 3 factorial 7 factorial end fraction plus fraction numerator 1 over denominator 5 factorial 5 factorial end fraction equals fraction numerator 8 to the power of a end exponent over denominator open parentheses 2 b close parentheses factorial blank end fraction comma blank$ then the value of $cos invisible function application A plus cos invisible function application B$ is

The side of triangle $A B C$ are in A.P. (order being $a comma blank b comma blank c$ ) and satisfy $fraction numerator 2 factorial over denominator 1 factorial 9 factorial end fraction plus fraction numerator 2 factorial over denominator 3 factorial 7 factorial end fraction plus fraction numerator 1 over denominator 5 factorial 5 factorial end fraction equals fraction numerator 8 to the power of a end exponent over denominator open parentheses 2 b close parentheses factorial blank end fraction comma blank$ then the value of $cos invisible function application A plus cos invisible function application B$ is

parallel

One of the general solutions of $4 sin invisible function application theta sin invisible function application 2 theta sin invisible function application 4 theta equals sin invisible function application 3 theta$ is

One of the general solutions of $4 sin invisible function application theta sin invisible function application 2 theta sin invisible function application 4 theta equals sin invisible function application 3 theta$ is

Which of the following is correct?

Which of the following is correct?

The number of solutions of $sec to the power of 2 end exponent invisible function application theta plus c o s e c to the power of 2 end exponent theta plus 2 blank c o s e c to the power of 2 end exponent theta equals 8 comma blank 0 less or equal than theta less or equal than pi divided by 2$ is

The number of solutions of $sec to the power of 2 end exponent invisible function application theta plus c o s e c to the power of 2 end exponent theta plus 2 blank c o s e c to the power of 2 end exponent theta equals 8 comma blank 0 less or equal than theta less or equal than pi divided by 2$ is

parallel

$I f sin invisible function application 2 theta equals cos invisible function application 3 theta blank a n d blank theta$ is an acute angle, then $sin invisible function application theta$ equals

$I f sin invisible function application 2 theta equals cos invisible function application 3 theta blank a n d blank theta$ is an acute angle, then $sin invisible function application theta$ equals

If $cos invisible function application B cos invisible function application C plus sin invisible function application B sin invisible function application C sin to the power of 2 end exponent invisible function application A equals 1 comma$ then triangle $A B C$ is

If $cos invisible function application B cos invisible function application C plus sin invisible function application B sin invisible function application C sin to the power of 2 end exponent invisible function application A equals 1 comma$ then triangle $A B C$ is

The number of values of $theta$ which satisfy the equation $sin invisible function application 3 theta minus sin invisible function application theta equals 4 cos to the power of 2 end exponent invisible function application theta minus 2 comma blank for all blank theta element of open square brackets 0 comma blank 2 pi close square brackets comma$ is

The number of values of $theta$ which satisfy the equation $sin invisible function application 3 theta minus sin invisible function application theta equals 4 cos to the power of 2 end exponent invisible function application theta minus 2 comma blank for all blank theta element of open square brackets 0 comma blank 2 pi close square brackets comma$ is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.