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Maths-

General

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Question

If the projection of point $P left parenthesis stack p with rightwards arrow on top right parenthesis$ on the plane $stack r with rightwards arrow on top times stack n with rightwards arrow on top equals q$ is the point $S left parenthesis stack s with rightwards arrow on top right parenthesis comma$ then

$\vec{s} = \frac{(q - \vec{p} \cdot \vec{n})}{| \vec{n} |^{2}}$
$\vec{s} = \vec{p} + \frac{(q - \vec{p} \cdot \vec{n}) \vec{n}}{| \vec{n} |^{2}}$
$\vec{s} = \vec{p} - \frac{(\vec{p} \cdot \vec{n}) \vec{n}}{| \vec{n} |^{2}}$
$\vec{s} = \vec{p} - \frac{(q - \vec{p} \cdot \vec{n}) \vec{n}}{| \vec{n} |^{2}}$

The correct answer is: $stack s with rightwards arrow on top equals stack p with rightwards arrow on top plus fraction numerator left parenthesis q minus stack p with rightwards arrow on top times stack n with rightwards arrow on top right parenthesis stack n with rightwards arrow on top over denominator vertical line stack n with rightwards arrow on top vertical line to the power of 2 end exponent end fraction$

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