Maths-
General
Easy
Question
If 
as well as 
are in G.P with the same common ratio, then the points 
.
- lie on a straight line
- lie on an ellipse
- lie on a circle
- are vertices of a triangle
The correct answer is: lie on a straight line
and so is 
Hence the points lie on a line, i.e., they are collinear.
Related Questions to study
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The range of 
for which the points 
and 
lie on opposite side of the line 2x+3y=6 is
The range of for which the points and lie on opposite side of the line 2x+3y=6 is
Maths-General
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The internal bisectors of the a 
, having the sides BC=3, CA=5 and AB =4 meet the sides BC, CA and AB in D, E and F respectively, the area of 
is
The internal bisectors of the a , having the sides BC=3, CA=5 and AB =4 meet the sides BC, CA and AB in D, E and F respectively, the area of is
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A straight line 
with negative slope passes through the point (8, 2) and cuts the positive coordinate axes at points P and Q As varies, the absolute minimum value of OP+OQ= where 
is the origin
A straight line with negative slope passes through the point (8, 2) and cuts the positive coordinate axes at points P and Q As varies, the absolute minimum value of OP+OQ= where is the origin
Maths-General
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Vertices of a variable triangle are (3, 4) 
and 
where 
Locus of its orthocenter is
Vertices of a variable triangle are (3, 4) and where Locus of its orthocenter is
Maths-General
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If (0,0), (a, 2), (2, b) form the vertices of an equilateral triangle, where a and b not lie between 0 and 2, then the value of 4(a
b)‐ab equals
If (0,0), (a, 2), (2, b) form the vertices of an equilateral triangle, where a and b not lie between 0 and 2, then the value of 4(ab)‐ab equals
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The lines 
and 
are concurrent if
The lines and are concurrent if
Maths-General
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Equation of the line perpendicular to 4x + 7y + 9 = 0 and such that the triangle formed by it with the coordinates axes forms an area of 3.5 sq. units is
Equation of the line perpendicular to 4x + 7y + 9 = 0 and such that the triangle formed by it with the coordinates axes forms an area of 3.5 sq. units is
Maths-General
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(0, 0) is the foot of the perpendicular from (4, 2) on a straight line. The equation of the line is
(0, 0) is the foot of the perpendicular from (4, 2) on a straight line. The equation of the line is
Maths-General
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The orthocentre of the triangle having vertices at (2, 3) (2, 5) (4, 3) is
The orthocentre of the triangle having vertices at (2, 3) (2, 5) (4, 3) is
Maths-General
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Each side of square is length 5. The centre of square is (3, 7) and one of the diagonals is parallel to y = x. Then the coordinates of its vertices are
Therefore, the coordinates of vertices of square are (1, 5) (1, 9) (5, 9) (5, 5).
Each side of square is length 5. The centre of square is (3, 7) and one of the diagonals is parallel to y = x. Then the coordinates of its vertices are
Maths-General
Therefore, the coordinates of vertices of square are (1, 5) (1, 9) (5, 9) (5, 5).
Maths-
The sides of a rhombus ABCD are parallel to the lines y = x + 2; y = 7x + 3. If the diagonals of the rhombus intersect at the point (1, 2) and the vertex A is on y – axis then A =
The sides of a rhombus ABCD are parallel to the lines y = x + 2; y = 7x + 3. If the diagonals of the rhombus intersect at the point (1, 2) and the vertex A is on y – axis then A =
Maths-General
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The quadrilateral formed by the lines 
+ y = 0; x + 
y = 0; x + y = 1; x + y + 1 = 0 is
The quadrilateral formed by the lines + y = 0; x + y = 0; x + y = 1; x + y + 1 = 0 is
Maths-General
Maths-
If 7x – y + 3 = 0; x + y – 3 = 0 are tow sides of an isosceles triangle and the third side passes through (1, 0) then the equation of the third side is
So here we used the concept of the triangles, and the equations of the lines to solve this problem. We know that the equation of a straight line in slope-intercept form is given as y = mx+c, so we used that here. So the equation of the third side is x + 3y - 1 = 0.
If 7x – y + 3 = 0; x + y – 3 = 0 are tow sides of an isosceles triangle and the third side passes through (1, 0) then the equation of the third side is
Maths-General
So here we used the concept of the triangles, and the equations of the lines to solve this problem. We know that the equation of a straight line in slope-intercept form is given as y = mx+c, so we used that here. So the equation of the third side is x + 3y - 1 = 0.
Maths-
All points lying inside the triangle formed by the points (1, 3) (5, 0) and (-1, 2) satisfy
All points lying inside the triangle formed by the points (1, 3) (5, 0) and (-1, 2) satisfy
Maths-General
Physics-
In Young's double slit experiment with a monochromatic light of wavelength 
, the fringe width is found to be 0.4 mm. When the slits are now illuminated with a light of wavelength 
the fringe width will be
In Young's double slit experiment with a monochromatic light of wavelength , the fringe width is found to be 0.4 mm. When the slits are now illuminated with a light of wavelength the fringe width will be
Physics-General
