Maths-
General
Easy
Question
If x is nearly equal to 1 such that 
, then the value of l is
- m
- n
- m + n
- m – n.
The correct answer is: m + n
Since x is nearly equal to 1.
\ x = 1 + h, where h is very small.
gives 
Related Questions to study
Maths-
Greatest term (numerically) in the expansion of 
if 
and 
is
Greatest term (numerically) in the expansion of if and is
Maths-General
Maths-
Co-efficient of 
in the expansion of 
is
Co-efficient of in the expansion of is
Maths-General
Chemistry-
The removal of two atoms or groups, one generally hydrogen 
and the other a leaving group 
resulting in the formation of unsaturated compound is known as elimination reaction.
In 
(elimination) reactions, the 
bond is broken heterolytic ally (in step 1) to form a carbocation (as in 
reaction) in which 
) is lost (rate determining step). The carbocation (in step 2) loses a proton from the 
-carbon atom by a base (nucleophile) to form an alkene. reaction is favoured in compounds in which the leaving group is at secondary 
or tertiary 
position. In 
formed simultaneously. 
reactions occur in one step through a transition state.
reactions are most common in haloalkanes (particularly, 
) and better the leaving group higher is the reaction. In reactions, both the leaving groups should be antiplanar.
cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
2-Bromobutane on heating with concentrated solution of alcoholic KOH gives major product as:
The removal of two atoms or groups, one generally hydrogen and the other a leaving group resulting in the formation of unsaturated compound is known as elimination reaction.
In (elimination) reactions, the bond is broken heterolytic ally (in step 1) to form a carbocation (as in reaction) in which ) is lost (rate determining step). The carbocation (in step 2) loses a proton from the -carbon atom by a base (nucleophile) to form an alkene. reaction is favoured in compounds in which the leaving group is at secondary or tertiary position. In formed simultaneously. reactions occur in one step through a transition state.
reactions are most common in haloalkanes (particularly, ) and better the leaving group higher is the reaction. In reactions, both the leaving groups should be antiplanar.
cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
2-Bromobutane on heating with concentrated solution of alcoholic KOH gives major product as:
Chemistry-General
Chemistry-
The removal of two atoms or groups, one generally hydrogen and the other a leaving group resulting in the formation of unsaturated compound is known as elimination reaction.
In (elimination) reactions, the bond is broken heterolytic ally (in step 1) to form a carbocation (as in reaction) in which ) is lost (rate determining step). The carbocation (in step 2) loses a proton from the -carbon atom by a base (nucleophile) to form an alkene. reaction is favoured in compounds in which the leaving group is at secondary or tertiary position. In formed simultaneously. reactions occur in one step through a transition state.
reactions are most common in haloalkanes (particularly, ) and better the leaving group higher is the reaction. In reactions, both the leaving groups should be antiplanar.
cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
Isopropyl chloride on heating with concentrated solution of ethanolic KOH gives mainly:
The removal of two atoms or groups, one generally hydrogen and the other a leaving group resulting in the formation of unsaturated compound is known as elimination reaction.
In (elimination) reactions, the bond is broken heterolytic ally (in step 1) to form a carbocation (as in reaction) in which ) is lost (rate determining step). The carbocation (in step 2) loses a proton from the -carbon atom by a base (nucleophile) to form an alkene. reaction is favoured in compounds in which the leaving group is at secondary or tertiary position. In formed simultaneously. reactions occur in one step through a transition state.
reactions are most common in haloalkanes (particularly, ) and better the leaving group higher is the reaction. In reactions, both the leaving groups should be antiplanar.
cb (Elimination unimolecular conjugate base) reaction involves the removal of proton by. a conjugate base (step 1) to produce carbanion which loses a leaving group to form an alkene (step 2) and is a slow step.
Isopropyl chloride on heating with concentrated solution of ethanolic KOH gives mainly:
Chemistry-General
Chemistry-
Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.
Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:
Above compound on treatment with NBS gives allylic bromides. How many product(s) will be obtained in this reaction?
Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.
Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:
Above compound on treatment with NBS gives allylic bromides. How many product(s) will be obtained in this reaction?
Chemistry-General
Chemistry-
Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.
Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:
Which of the following sequences is correct about C-H bond energy?
Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.
Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:
Which of the following sequences is correct about C-H bond energy?
Chemistry-General
Chemistry-
Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.
Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:
Consider the three types of C-H bonds in cyclohexene.
Which of the following is/are correctly matched?
Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.
Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:
Consider the three types of C-H bonds in cyclohexene.
Which of the following is/are correctly matched?
Chemistry-General
Chemistry-
Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.
Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:
In the treatment of cyclohexene with NBS, which of the following products will be least stable?
Karl Ziegler reported that alkenes react with N-bromosuccinimide (NBS) in presence of light to give products resulting from substitution of hydrogen by bromjne at the allylic position, i.e., the position next to the double bond. Let us consider the halogenation of cyclohexene.
Energy level diagram for allylic, vinylic and alkylic, free radicals is .given below:
In the treatment of cyclohexene with NBS, which of the following products will be least stable?
Chemistry-General
Chemistry-
The high reactivity of alkyl halides can be explained in terms of nature of C-X bond which is highly polarised covalent bond due to large difference in the electronegativities of carbon and halogen .atom. This polarity is responsible for the nucleophilic substitution reactions of alky- halides which mostly occur by and 
mechanisms reaction is a two step process . and in the first step, R-X ionises to give carbocation (slow process). In the second step, the nucleophile attacks the carbocation from either side to form the product (fast process). In reaction, there can be racemization and inversion. reaction is favoured by heavy (bulky) groups on the carbon atom attached to halogens. i.e., 
In reaction, the strong nucleophile OH- attacks from the opposite side of the chlorine atom to give an intermediate (transition state). which breaks to yield the product (alcohol) and leavj.ng 
group. The alcohol has a configuration opposite to drat 'of the bromide and is said to proceed with inversion of configuration. reaction is favoured by small groups on the carbon atom attached to halogen i.e., 
The main product formed in the following reaction is:
The high reactivity of alkyl halides can be explained in terms of nature of C-X bond which is highly polarised covalent bond due to large difference in the electronegativities of carbon and halogen .atom. This polarity is responsible for the nucleophilic substitution reactions of alky- halides which mostly occur by and mechanisms reaction is a two step process . and in the first step, R-X ionises to give carbocation (slow process). In the second step, the nucleophile attacks the carbocation from either side to form the product (fast process). In reaction, there can be racemization and inversion. reaction is favoured by heavy (bulky) groups on the carbon atom attached to halogens. i.e.,
In reaction, the strong nucleophile OH- attacks from the opposite side of the chlorine atom to give an intermediate (transition state). which breaks to yield the product (alcohol) and leavj.ng group. The alcohol has a configuration opposite to drat 'of the bromide and is said to proceed with inversion of configuration. reaction is favoured by small groups on the carbon atom attached to halogen i.e.,
The main product formed in the following reaction is:
Chemistry-General
Chemistry-
Compound 
undergoes intramolecular nucleophilic substitution of the type .... giving .
Compound undergoes intramolecular nucleophilic substitution of the type .... giving .
Chemistry-General
Chemistry-
In the following compounds, nucleophile and the leaving groups are in the same molecule:
I) 
II) 
III) 
IV) 
These dual nature species can undergo intramolecular and intermolecular nucleophilic substitution. Intramolecular substitution reaction is possible in:
In the following compounds, nucleophile and the leaving groups are in the same molecule:
I)
II)
III)
IV)
These dual nature species can undergo intramolecular and intermolecular nucleophilic substitution. Intramolecular substitution reaction is possible in:
Chemistry-General
Chemistry-
Ullmann reaction is given by:
Ullmann reaction is given by:
Chemistry-General
Chemistry-
The major product of the reaction,
with HBr is:
The major product of the reaction,
with HBr is:
Chemistry-General
Chemistry-
The reaction given
is:
The reaction given
is:
Chemistry-General
Chemistry-
In the reaction,
the compound (C) is:
In the reaction,
the compound (C) is:
Chemistry-General
