Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

In a certain test there are n questions. In this test 2n–i student gave wrong answers to atleast i questions where i = 1, 2, 3 ..... n . If the total no. of wrong answer given is 2047. Then n is equal to-
10
11
12
13

The correct answer is: 11

Related Questions to study

In an examination of 9 papers a candidate has to pass in more papers than the number of papers in which he fails in order to be successful. The number of ways in which he can be unsuccessful is-

In an examination of 9 papers a candidate has to pass in more papers than the number of papers in which he fails in order to be successful. The number of ways in which he can be unsuccessful is-

At an election, a voter may vote for any number of candidates not greater than the number to be chosen. There are 10 candidates and 5 members are to be chosen. The number of ways in which a voter may vote for at least one candidate is given by-

At an election, a voter may vote for any number of candidates not greater than the number to be chosen. There are 10 candidates and 5 members are to be chosen. The number of ways in which a voter may vote for at least one candidate is given by-

How many 7 digit numbers can be written using three digits 1, 2 and 3 under the condition that the digits 2 occurs twice in each number ?

How many 7 digit numbers can be written using three digits 1, 2 and 3 under the condition that the digits 2 occurs twice in each number ?

parallel

A is a set containing n elements. A subset P of A is chosen. The set A is reconstructed replacing the elements of P. A subset Q of A is again chosen. The number of ways of choosing P and Q so that P  Q contains exactly two elements is-

A is a set containing n elements. A subset P of A is chosen. The set A is reconstructed replacing the elements of P. A subset Q of A is again chosen. The number of ways of choosing P and Q so that P  Q contains exactly two elements is-

There are p points in space, no four of which are in the same plane with the exception of q points which are all in the same plane. The number of different planes determined by the points is-

There are p points in space, no four of which are in the same plane with the exception of q points which are all in the same plane. The number of different planes determined by the points is-

The number of ways to fill each of the four cells of the table with a distinct natural number such that the sum of the numbers is 10 and the sums of the numbers placed diagonally are equal, is-

The number of ways to fill each of the four cells of the table with a distinct natural number such that the sum of the numbers is 10 and the sums of the numbers placed diagonally are equal, is-
Maths-General

parallel

Two teams are to play a series of 5 matches between them. A match ends in a win or loss or draw for a team. A number of people forecast the result of each match and no two people make the same forecast for the series of matches. The smallest group of people in which one person forecasts correctly for all the matches will contain n people, where n is-

Two teams are to play a series of 5 matches between them. A match ends in a win or loss or draw for a team. A number of people forecast the result of each match and no two people make the same forecast for the series of matches. The smallest group of people in which one person forecasts correctly for all the matches will contain n people, where n is-

The number of ways in which, 2n things of one sort, 2n things of another sort and 2n of a third sort can be divided between two person so that each get 3n things is -

The number of ways in which, 2n things of one sort, 2n things of another sort and 2n of a third sort can be divided between two person so that each get 3n things is -

The current passing through a choke coil of 5 henry is decreasing at the rate of $2 blank a m p e r e divided by s e c$ . The e.m.f. developing across the coil is

The current passing through a choke coil of 5 henry is decreasing at the rate of $2 blank a m p e r e divided by s e c$ . The e.m.f. developing across the coil is

Physics-General

parallel

The energy stored in an inductor of self inductance $L$ henry carrying a current of 1 A is

The energy stored in an inductor of self inductance $L$ henry carrying a current of 1 A is

Physics-General

If $tan invisible function application open parentheses A minus B close parentheses equals 1$ and $sec invisible function application open parentheses A plus B close parentheses equals 2 divided by square root of 3 comma blank$ then the smallest positive values of $A blank$ and $B comma$ respectively, are

If $tan invisible function application open parentheses A minus B close parentheses equals 1$ and $sec invisible function application open parentheses A plus B close parentheses equals 2 divided by square root of 3 comma blank$ then the smallest positive values of $A blank$ and $B comma$ respectively, are

Let $n$ be a positive integer such that $sin invisible function application fraction numerator pi over denominator 2 n end fraction plus cos invisible function application fraction numerator pi over denominator 2 n end fraction equals fraction numerator square root of x over denominator 2 end fraction.$ Then

Let $n$ be a positive integer such that $sin invisible function application fraction numerator pi over denominator 2 n end fraction plus cos invisible function application fraction numerator pi over denominator 2 n end fraction equals fraction numerator square root of x over denominator 2 end fraction.$ Then

parallel

In triangle $A B C comma$ if $sin invisible function application A cos invisible function application B equals fraction numerator 1 over denominator 4 end fraction$ and $blank 3 tan invisible function application A equals tan invisible function application B$ , then $cot to the power of 2 end exponent invisible function application A$ is equal to

In triangle $A B C comma$ if $sin invisible function application A cos invisible function application B equals fraction numerator 1 over denominator 4 end fraction$ and $blank 3 tan invisible function application A equals tan invisible function application B$ , then $cot to the power of 2 end exponent invisible function application A$ is equal to

If $y equals open parentheses 1 plus tan invisible function application A close parentheses open parentheses 1 minus tan invisible function application B close parentheses blank$ where $blank A minus B equals fraction numerator pi over denominator 4 end fraction comma$ then $open parentheses y plus 1 close parentheses to the power of y plus 1 end exponent blank$ is equal to

If $y equals open parentheses 1 plus tan invisible function application A close parentheses open parentheses 1 minus tan invisible function application B close parentheses blank$ where $blank A minus B equals fraction numerator pi over denominator 4 end fraction comma$ then $open parentheses y plus 1 close parentheses to the power of y plus 1 end exponent blank$ is equal to

The number of solutions of $sin invisible function application x plus sin invisible function application 2 x plus sin invisible function application 3 x equals cos invisible function application x plus cos invisible function application 2 x plus cos invisible function application 3 x comma blank 0 less or equal than x less or equal than 2 pi comma$ is

The number of solutions of $sin invisible function application x plus sin invisible function application 2 x plus sin invisible function application 3 x equals cos invisible function application x plus cos invisible function application 2 x plus cos invisible function application 3 x comma blank 0 less or equal than x less or equal than 2 pi comma$ is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.