Maths-
General
Easy
Question
In 
Hint:
To simplify the given equation we will use a+ b+ c = 2s, tan
=
and tan
=
then using other trigonometric identities we will simplify the equation.
The correct answer is: 
As, a+ b+ c = 2s, tan
=
, tan
=
we have, (a +b +c) (tan
+tan
)

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