Question
In the interval 
the equation 
has
- no solution
- a unique solution
- two solutions
- infinitely many solutions
Hint:
In this question, we have given that in the interval of . We have to find it which type of solution it has. We know that 
then we can take antilog, b = ca. Using find the solution of equation.
The correct answer is: a unique solution
Here we have to find it which type of solution it has.
Firstly, we have given,
We know if then we can take antilog, b = ca
So, we can write,
Cos2 θ = sin2 θ
1 – 2 sin2 θ = sin2 θ [ since, cos2 θ = 1 – 2 sin2 θ ]
3sin2 θ = 1
sin2 θ = 
sin θ = ±
Base of log is never negative,
sin θ =
Therefore, it has only one solution, that means it has unique solution.
The correct answer is a unique solution.
In this question, we have to find type of solution, here, we know if then we can take antilog, b = ca, and cos2 θ = 1 – 2 sin2 θ . Remember these terms and find the solution easily.
Related Questions to study
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,then
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,
,2π and since we also need x≠, for tanx and x≠0,2π for cotx all the solutions.
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] is :
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,then
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If 
If
The most general solution of the equations 
is
The most general solution of the equations is
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is
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=
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Let S = 
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Let S = The sun of all distinct solution of the equation
A wave motion has the function 
The graph in figure shows how the displacement 
at a fixed point varies with time 
Which one of the labelled points shows a displacement equal to that at the position 
at time 
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, the equation 
has
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Which of the following pairs of compounds are functional isomers?
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Let 
be such that 
and 
Then 
cannot satisfy
In this question we have to find the the which region ϕ cannot satisfy. In this question more than one option is correct. Here firstly solve the given equation. Remember that, , tan x + cot x = 
.
Let be such that and Then cannot satisfy
In this question we have to find the the which region ϕ cannot satisfy. In this question more than one option is correct. Here firstly solve the given equation. Remember that, , tan x + cot x = .
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has a solution 
with 
, is
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are
Roots of the equation are
