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Question

Let $a equals 111 horizontal ellipsis 1$ (55 digits), $b equals 1 plus 10 plus 10 to the power of 2 end exponent plus horizontal ellipsis plus 10 to the power of 4 end exponent comma blank c equals 1 plus 10 to the power of 5 end exponent plus 10 to the power of 10 end exponent plus 10 to the power of 15 end exponent plus horizontal ellipsis plus 10 to the power of 50 end exponent$ , then

$a = b + c$
$a = b c$
$b = a c$
$c = a b$

The correct answer is: $a equals b c$

$a equals 1 plus 10 plus 10 to the power of 2 end exponent plus horizontal ellipsis plus 10 to the power of 54 end exponent$
$equals fraction numerator 10 to the power of 55 end exponent minus 1 over denominator 10 minus 1 end fraction equals fraction numerator 10 to the power of 55 end exponent minus 1 over denominator 10 to the power of 5 end exponent minus 1 end fraction cross times fraction numerator 10 to the power of 5 end exponent minus 1 over denominator 10 minus 1 end fraction equals b c$

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