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One of the general solutions of 4 sin invisible function application theta sin invisible function application 2 theta sin invisible function application 4 theta equals sin invisible function application 3 theta is

  1. fraction numerator open parentheses 3 n plus-or-minus 1 close parentheses pi over denominator 12 end fraction comma for all blank n element of Z  
  2. open parentheses 4 n plus-or-minus 1 close parentheses pi divided by 9 comma for all blank n element of Z  
  3. fraction numerator open parentheses 3 n plus-or-minus 1 close parentheses pi over denominator 9 end fraction comma for all blank n element of Z  
  4. open parentheses 3 n plus-or-minus 1 close parentheses pi divided by 3 comma for all blank n element of Z  

The correct answer is: fraction numerator open parentheses 3 n plus-or-minus 1 close parentheses pi over denominator 9 end fraction comma for all blank n element of Z


    We have 4 sin invisible function application theta sin invisible function application 2 theta sin invisible function application 4 theta equals 3 sin invisible function application theta minus 4 sin to the power of 3 end exponent invisible function application theta
    rightwards double arrow sin invisible function application theta open square brackets 4 sin invisible function application 2 theta sin invisible function application 4 theta minus 3 plus 4 sin to the power of 2 end exponent invisible function application theta close square brackets equals 0
    rightwards double arrow sin invisible function application theta open square brackets 2 blank open parentheses cos invisible function application 2 theta minus cos invisible function application 6 theta close parentheses minus 3 plus 2 open parentheses 1 minus cos invisible function application 2 theta close parentheses close square brackets equals 0
    rightwards double arrow sin invisible function application theta open parentheses negative 2 cos invisible function application 6 theta minus 1 close parentheses equals 0
    rightwards double arrow sin invisible function application theta equals 0 or cos invisible function application 6 theta equals negative 1 divided by 2
    rightwards double arrow theta equals n pi orblank 6 theta equals 2 n pi plus-or-minus 2 pi divided by 3 comma blank for all blank n element of Z
    equals n pi orblank theta equals open parentheses 3 n plus-or-minus 1 close parentheses blank pi divided by 9 comma blank for all blank n element of Z

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