Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

Statement-1 : If f(x) = $fraction numerator left parenthesis e to the power of k x end exponent minus 1 right parenthesis sin invisible function application blank k x over denominator 4 x to the power of 2 end exponent end fraction$ (x $not equal to$ 0) and f(0) = 9 is continuous at x = 0 then k = ± 6.
Statement-2 : For continuous function $stack l i m with x rightwards arrow 0 below$ f(x) = f(0)

If both (A) and (R) are true, and (R) is the correct explanation of (A).
If both (A) and (R) are true but (R) is not the correct explanation of (A).
If (A) is true but (R) is false.
If (A) is false but (R) is true.

The correct answer is: If both (A) and (R) are true but (R) is not the correct explanation of (A).

Related Questions to study

Statement-I : Let f(x) = $fraction numerator 1 minus tan invisible function application x over denominator 4 x minus pi end fraction$ , x $not equal to$ $fraction numerator pi over denominator 4 end fraction$ , x $element of$ $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ . If f(x) is continuous in $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ , Then f $open parentheses fraction numerator pi over denominator 4 end fraction close parentheses$ = $negative fraction numerator 1 over denominator 2 end fraction$ .
Statement-II : f(x) is continuous at x = a if $stack l i m with x rightwards arrow a below$ f(x) = f(a)

Statement-I : Let f(x) = $fraction numerator 1 minus tan invisible function application x over denominator 4 x minus pi end fraction$ , x $not equal to$ $fraction numerator pi over denominator 4 end fraction$ , x $element of$ $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ . If f(x) is continuous in $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ , Then f $open parentheses fraction numerator pi over denominator 4 end fraction close parentheses$ = $negative fraction numerator 1 over denominator 2 end fraction$ .
Statement-II : f(x) is continuous at x = a if $stack l i m with x rightwards arrow a below$ f(x) = f(a)

Statement 1 : f(x) = xⁿ sin $open parentheses fraction numerator 1 over denominator x end fraction close parentheses$ is differentiable for all real values of x (n $greater or equal than$ 2).
Statement 2 : For n $greater or equal than$ 2, Right derivative = left derivative (for all real values of x).

Statement 1 : f(x) = xⁿ sin $open parentheses fraction numerator 1 over denominator x end fraction close parentheses$ is differentiable for all real values of x (n $greater or equal than$ 2).
Statement 2 : For n $greater or equal than$ 2, Right derivative = left derivative (for all real values of x).

If H₂O₂ is mixed with Fe²⁺, which reaction is more likely:

If H₂O₂ is mixed with Fe²⁺, which reaction is more likely:

Chemistry-General

parallel

For the following cell reaction $P b open parentheses s close parentheses plus H g subscript 2 end subscript S O subscript 4 end subscript open parentheses s close parentheses P b S O subscript 4 end subscript open parentheses s close parentheses plus 2 H g open parentheses l close parentheses E subscript text cell end text end subscript superscript ring operator end superscript equals 0.92 V comma$ $K subscript S p end subscript open parentheses P b S O subscript 4 end subscript close parentheses equals 2 cross times 10 to the power of negative 8 end exponent$ , $K subscript S p end subscript open parentheses H g S O subscript 4 end subscript close parentheses equals 1 cross times 10 to the power of negative 6 end exponent$ Hence, E_cell is:

For the following cell reaction $P b open parentheses s close parentheses plus H g subscript 2 end subscript S O subscript 4 end subscript open parentheses s close parentheses P b S O subscript 4 end subscript open parentheses s close parentheses plus 2 H g open parentheses l close parentheses E subscript text cell end text end subscript superscript ring operator end superscript equals 0.92 V comma$ $K subscript S p end subscript open parentheses P b S O subscript 4 end subscript close parentheses equals 2 cross times 10 to the power of negative 8 end exponent$ , $K subscript S p end subscript open parentheses H g S O subscript 4 end subscript close parentheses equals 1 cross times 10 to the power of negative 6 end exponent$ Hence, E_cell is:

Chemistry-General

Extraction of zinc from zinc blende is achieved by-

Extraction of zinc from zinc blende is achieved by-

Chemistry-General

When the sample of Cu with Zn impurity is to be purified by electrolysis, the appropriate electrodes are-
CathodeAnode

When the sample of Cu with Zn impurity is to be purified by electrolysis, the appropriate electrodes are-
CathodeAnode

Chemistry-General

parallel

Which statement is not correct for Kohlrausch law?

Which statement is not correct for Kohlrausch law?

Chemistry-General

The equivalent conductivity of 0.1 M weak acid is 100 times less than that at infinite dilution. The degree of dissociation of weak electrolyte at 0.1 M is –

The equivalent conductivity of 0.1 M weak acid is 100 times less than that at infinite dilution. The degree of dissociation of weak electrolyte at 0.1 M is –

Chemistry-General

3 faraday of electricity are passed through molten Al₂O₃, aqueous solution of CuSO₄ and molten NaCl taken in three different electrolytic cells. The amount of Al, Cu and Na deposited at the cathodes will be in the ratio of –

3 faraday of electricity are passed through molten Al₂O₃, aqueous solution of CuSO₄ and molten NaCl taken in three different electrolytic cells. The amount of Al, Cu and Na deposited at the cathodes will be in the ratio of –

Chemistry-General

parallel

Beryllium is placed above magnesium in the II group. Beryllium dust, therefore, when added to MgCl₂ solution will –

Beryllium is placed above magnesium in the II group. Beryllium dust, therefore, when added to MgCl₂ solution will –

Chemistry-General

Metals can be prevented from rusting by –

Metals can be prevented from rusting by –

Chemistry-General

The thermodynamic efficiency of cell is given by –

The thermodynamic efficiency of cell is given by –

Chemistry-General

parallel

The following facts are available $table row cell 2 X to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow 2 Y to the power of minus end exponent plus X subscript 2 end subscript end cell row cell 2 W to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow text end text text N end text text o end text text end text text r end text text e end text text a end text text c end text text t end text text i end text text o end text text n end text text end text end cell row cell 2 Z to the power of minus end exponent plus X subscript 2 end subscript rightwards arrow 2 X to the power of minus end exponent plus Z subscript 2 end subscript end cell end table$ Which of the following is correct?

The following facts are available $table row cell 2 X to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow 2 Y to the power of minus end exponent plus X subscript 2 end subscript end cell row cell 2 W to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow text end text text N end text text o end text text end text text r end text text e end text text a end text text c end text text t end text text i end text text o end text text n end text text end text end cell row cell 2 Z to the power of minus end exponent plus X subscript 2 end subscript rightwards arrow 2 X to the power of minus end exponent plus Z subscript 2 end subscript end cell end table$ Which of the following is correct?

Chemistry-General

A standard hydrogen electrode has zero electrode potential because:

A standard hydrogen electrode has zero electrode potential because:

Chemistry-General

Given that $E subscript F e to the power of 3 plus end exponent divided by F e to the power of 2 plus end exponent end subscript equals negative 0.36 V$ and $E subscript F e to the power of 2 plus end exponent divided by F e end subscript equals negative 0.439 V$ respectively. Therefore value of $E to the power of ring operator end exponent F e to the power of 3 plus end exponent comma F e to the power of 2 plus end exponent divided by P t$ is :

Given that $E subscript F e to the power of 3 plus end exponent divided by F e to the power of 2 plus end exponent end subscript equals negative 0.36 V$ and $E subscript F e to the power of 2 plus end exponent divided by F e end subscript equals negative 0.439 V$ respectively. Therefore value of $E to the power of ring operator end exponent F e to the power of 3 plus end exponent comma F e to the power of 2 plus end exponent divided by P t$ is :

Chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.