Maths-
General
Easy

Question

The general solution of the equation, fraction numerator 1 minus sin space x plus midline horizontal ellipsis comma plus left parenthesis negative 1 right parenthesis to the power of n sin to the power of n space x plus midline horizontal ellipsis straight infinity over denominator 1 plus sin space x plus midline horizontal ellipsis plus sin to the power of n space x plus midline horizontal ellipsis straight infinity end fraction equals fraction numerator 1 minus cos space 2 x over denominator 1 plus cos space 2 x end fraction is :

  1. left parenthesis negative 1 right parenthesis to the power of straight n pi divided by 3 plus straight n pi
  2. left parenthesis negative 1 right parenthesis to the power of straight n pi divided by 6 plus straight n pi
  3. left parenthesis negative 1 right parenthesis to the power of n plus 1 end exponent pi divided by 6 plus n pi
  4. left parenthesis negative 1 right parenthesis to the power of straight n minus 1 end exponent pi divided by 3 plus straight n pi

hintHint:

In this question, we have given an equation, that is.
fraction numerator 1 minus sin x plus midline horizontal ellipsis. comma plus open parentheses 1 close parentheses to the power of n space sin to the power of n x plus midline horizontal ellipsis space. infinity over denominator 1 plus sin x plus midline horizontal ellipsis. comma plus space sin to the power of n x plus midline horizontal ellipsis space. infinity end fraction equals fraction numerator 1 minus cos 2 x over denominator 1 plus cos 2 x end fraction
We have to find the general solution of solution. We have given series of sine, put the sum to that and find the solution.

The correct answer is: left parenthesis negative 1 right parenthesis to the power of straight n pi divided by 6 plus straight n pi


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