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Maths-

General

Easy

Question

The harmonic mean of the roots of the equation $open parentheses 5 plus square root of 2 close parentheses x to the power of 2 end exponent minus open parentheses 4 plus square root of 5 close parentheses x plus 8 plus 2 square root of 5 equals 0$ is

2
4
6
8

The correct answer is: 4

Harmonic mean $H$ of roots $alpha$ and $beta$ is
$H equals fraction numerator 2 alpha beta over denominator alpha plus beta end fraction equals fraction numerator 2 fraction numerator 5 plus 2 square root of 5 over denominator 5 plus square root of 2 end fraction over denominator fraction numerator 4 plus square root of 5 over denominator 5 plus square root of 2 end fraction end fraction equals 4$

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Maths-General

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