Maths-
General
Easy

Question

The length of the perpendicular from the incentre of the triangle formed by the axes and the line fraction numerator x over denominator 3 end fraction plus fraction numerator y over denominator 4 end fraction equals 1 to the hypotenuse is

  1. 4    
  2. 3    
  3. 2    
  4. 1    

The correct answer is: 1

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If theta is the angle between two adjacent sides of a parallelogram and p, q are the distances between the parallel sides, then the area of the parallelogram

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fraction numerator d over denominator d x end fraction open parentheses fraction numerator a x plus b over denominator c x plus d end fraction close parentheses equals

For such questions, we should know how to use u by v method.

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For such questions, we should know how to use u by v method.

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fraction numerator d over denominator d x end fraction open parentheses e to the power of x to the power of 2 end exponent end exponent a to the power of x end exponent close parentheses equals

For such questions, we should know u.v method.

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For such questions, we should know u.v method.

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fraction numerator d over denominator d x end fraction open parentheses Tan to the power of negative 1 end exponent invisible function application square root of fraction numerator 1 minus c o s invisible function application x over denominator 1 plus c o s invisible function application x end fraction end root close parentheses equals

We should know different formulas to solve such questions.

fraction numerator d over denominator d x end fraction open parentheses Tan to the power of negative 1 end exponent invisible function application square root of fraction numerator 1 minus c o s invisible function application x over denominator 1 plus c o s invisible function application x end fraction end root close parentheses equals

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We should know different formulas to solve such questions.

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fraction numerator d over denominator d x end fraction open parentheses Tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a minus x over denominator 1 plus infinity x end fraction close parentheses close parentheses equals

For such questions, we should know different formulas.

fraction numerator d over denominator d x end fraction open parentheses Tan to the power of negative 1 end exponent invisible function application open parentheses fraction numerator a minus x over denominator 1 plus infinity x end fraction close parentheses close parentheses equals

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For such questions, we should know different formulas.

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fraction numerator d over denominator d x end fraction open parentheses cosec to the power of negative 1 end exponent invisible function application open parentheses e to the power of 2 x plus 1 end exponent close parentheses close parentheses equals

For such questions, we should know different formulas.

fraction numerator d over denominator d x end fraction open parentheses cosec to the power of negative 1 end exponent invisible function application open parentheses e to the power of 2 x plus 1 end exponent close parentheses close parentheses equals

Maths-General

For such questions, we should know different formulas.

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fraction numerator d over denominator d x end fraction open parentheses fraction numerator sin invisible function application x over denominator 1 plus c o s invisible function application x end fraction close parentheses equals

The alternate method to solve this will be using u by method. It is method used in differentiation when we have a condition of numerator and denominator.

fraction numerator d over denominator d x end fraction open parentheses fraction numerator sin invisible function application x over denominator 1 plus c o s invisible function application x end fraction close parentheses equals

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The alternate method to solve this will be using u by method. It is method used in differentiation when we have a condition of numerator and denominator.

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