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Maths-

General

Easy

Question

The number of solutions of the equation
sin 2x = [1 + sin 2x] + [1 cos 2x] in $open square brackets 0 comma fraction numerator pi over denominator 2 end fraction close square brackets$ where [.] is the greatest
integer function is

0
1
2
4

The correct answer is: 0

sin 2x = 1 $x element of open square brackets 0 comma fraction numerator pi over denominator 4 end fraction close square brackets$ = 2 $x element of open square brackets fraction numerator pi over denominator 4 end fraction comma fraction numerator pi over denominator 2 end fraction close square brackets$

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