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General
Easy

Question

The solution set of the inequality log1 fifth (2x + 5) + log5 (16 x 2) 1 is

  1. open parentheses negative fraction numerator 5 over denominator 2 end fraction comma 1 close parentheses    
  2. left square bracket 1 comma left parenthesis d right parenthesis    
  3. (1, 4]    
  4. open parentheses negative fraction numerator 5 over denominator 2 end fraction comma 4 close parentheses    

The correct answer is: left square bracket 1 comma left parenthesis d right parenthesis


    l o g subscript 5 end subscript invisible function application fraction numerator open parentheses 16 minus x to the power of 2 end exponent close parentheses over denominator left parenthesis 2 x plus 5 right parenthesis end fraction less or equal than 1
    16 x2 10x + 25
    x2 + 10x + 9 0
    x 1 or x 9
    But x > - 5 over 2 and 4 < x < 4
    x [ 1, (d)

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