Maths-
General
Easy
Question
The parabola y2 = 4x and the circle (x – 6)2 + y2 = r2 will have no common tangent, if ‘r’ is equal to -
- r >
- r <
- r >
- r (,)
The correct answer is: r <
Any normal of parabola is y = –tx + 2t + t3. If it pass through (6, 0), then, –6t + 2t + t3 = 0
t = 0, t2 = 4
Thus A ≡ (4, 4)
Thus, for no common tangent, AC > > r r < .
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