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Question

$open curly brackets open x element of R divided by l o g open square brackets open parentheses 1.6 close parentheses to the power of 1 minus x 2 end exponent minus open parentheses 0.625 close parentheses to the power of 6 open parentheses 1 plus x close parentheses end exponent close square brackets element of R close curly brackets equals close$

$(- \infty, - 1) \cup (7, \infty)$
(-1,5)
(1,7)
(-1,7)

The correct answer is: (-1,7)

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parallel

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I) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is real for each $fraction numerator p over denominator q end fraction element of Q$
II) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is a complex number for each $fraction numerator p over denominator q end fraction element of Q$ Which of the following is correct?

parallel

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