Physics-

General

Easy

Question

A beam of fast moving alpha particles were directed towards a thin film of gold. The parts $A to the power of ´ end exponent comma B to the power of ´ end exponent$ and $C to the power of ´ end exponent$ of the transmitted and reflected beams corresponding to the incident parts A, B and C of the beam, are shown in the adjoining diagram. The number of alpha particles in

$B^{}$ '/>will be minimum and in $C^{}$ '/>maximum
$A^{}$ '/>will be maximum and in $B^{}$ '/>minimum
$A^{}$ '/>will be minimum and in $B^{}$ '/>maximum
$C^{}$ '/>will be minimum and in $B^{}$ '/>maximum

The correct answer is: $A to the power of ´ end exponent$ will be maximum and in $B to the power of ´ end exponent$ minimum

Because atom is hollow and whole mass of atom is concentrated in a small centre called nucleus.

The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength $lambda$ is emitted. The wavelength of photon produced during its transition from $fraction numerator 4 E over denominator 3 end fraction$ level to E is

Physics-General

General

Physics-

Energy levels A, B, C of a certain atom corresponding to increasing values of energy i.e. $E subscript A end subscript less than E subscript B end subscript less than E subscript C end subscript$ . If $lambda subscript 1 end subscript comma lambda subscript 2 end subscript comma lambda subscript 3 end subscript$ are the wavelengths of radiations corresponding to the transitions C to B, B to A and C to A respectively, which of the following statements is correct

Physics-General

General

Physics-

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

Physics-General

General

Physics-

The energy levels of the hydrogen spectrum is shown in figure. There are some transitions A, B, C, D and E. Transition A, B and C respectively represent

Physics-General

General

Physics-

In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number)

Physics-General

General

Physics-

If the potential difference between the anode and cathode of the X-ray tube is increases

Physics-General

General

Physics-

Two large parallel plates are connected with the terminal of 100 V power supply. These plates have a fine hole at the centre. An electron having energy 200 eV is so directed that it passes through the holes. When it comes out it's de-Broglie wavelength is

Physics-General

General

Physics-

Light of wavelength 2475 Å is incident on barium. Photoelectrons emitted describe a circle of radius 100 cm by a magnetic field of flux density $fraction numerator 1 over denominator square root of 17 end fraction cross times 1 0 to the power of negative 5 end exponent$ Tesla. Work function of the barium is (Given $fraction numerator e over denominator m end fraction equals 1.7 cross times 1 0 to the power of 11 end exponent right parenthesis$

Physics-General

General

Physics-

If a voltage applied to an X-ray tube is increased to 1.5 times the minimum wavelength $left parenthesis lambda subscript m i n end subscript$ of an X-ray continuous spectrum shifts by $capital delta lambda equals 26 p m$ . The initial voltage applied to the tube is

Physics-General

General

Physics-

The figure shows different graphs between stopping potential $left parenthesis V subscript 0 end subscript right parenthesis$ and frequency (n) for photosensitive surface of cesium, potassium, sodium and lithium. The plots are parallel. Correct ranking of the targets according to their work function greatest first will be

Physics-General

General

Maths-

f(x) = $open curly brackets table row cell 2 x minus 1 end cell cell i f end cell cell x greater than 2 end cell row k cell i f end cell cell x equals 2 end cell row cell x to the power of 2 end exponent minus 1 end cell cell i f end cell cell x less than 2 end cell end table close$ is continuous at x = 2 then k =

Maths-General

General

Maths-

$f open parentheses x close parentheses equals open square brackets x minus 5 close square brackets plus open square brackets 5 minus x close square brackets blank$ is continuous on

Maths-General

General

The value of f (0) so that f(x) = $open parentheses 1 plus 5 x close parentheses to the power of 1 divided by x end exponent$ is continuous at x = 0 is

We have to be careful that denominator is not zero. We have to readjust the function in a way we will not get zero at denominator for the function to be continuous at that point. And, we have to know different formulas of limit.

The value of f (0) so that f(x) = $open parentheses 1 plus 5 x close parentheses to the power of 1 divided by x end exponent$ is continuous at x = 0 is

GeneralGeneral

General

Maths-

If $blank f open parentheses x close parentheses equals fraction numerator e to the power of fraction numerator 1 over denominator x to the power of 2 end exponent end fraction end exponent over denominator e to the power of fraction numerator 1 over denominator x to the power of 2 end exponent end fraction end exponent minus 1 end fraction comma x not equal to 0 comma f open parentheses 0 close parentheses equals 1 blank$ then $f blank$ at $blank x equals 0 blank$ is

Maths-General

General

Maths-

$fraction numerator t a n blank 80 to the power of 0 end exponent blank minus blank t a n blank 10 to the power of 0 end exponent over denominator t a n invisible function application 70 to the power of 0 end exponent blank end fraction$

Maths-General

Have a query? Ask a Tutor!!

Can’t find what you’re looking for?

$B^{}$ '/>will be minimum and in $C^{}$ '/>maximum
$A^{}$ '/>will be maximum and in $B^{}$ '/>minimum
$A^{}$ '/>will be minimum and in $B^{}$ '/>maximum
$C^{}$ '/>will be minimum and in $B^{}$ '/>maximum

The correct answer is: $A to the power of ´ end exponent$ will be maximum and in $B to the power of ´ end exponent$ minimum

Because atom is hollow and whole mass of atom is concentrated in a small centre called nucleus.

Related Questions to study

The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength $lambda$ is emitted. The wavelength of photon produced during its transition from $fraction numerator 4 E over denominator 3 end fraction$ level to E is

The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength $lambda$ is emitted. The wavelength of photon produced during its transition from $fraction numerator 4 E over denominator 3 end fraction$ level to E is

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

The energy levels of the hydrogen spectrum is shown in figure. There are some transitions A, B, C, D and E. Transition A, B and C respectively represent

The energy levels of the hydrogen spectrum is shown in figure. There are some transitions A, B, C, D and E. Transition A, B and C respectively represent

In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number)

In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number)

If the potential difference between the anode and cathode of the X-ray tube is increases

If the potential difference between the anode and cathode of the X-ray tube is increases

Two large parallel plates are connected with the terminal of 100 V power supply. These plates have a fine hole at the centre. An electron having energy 200 eV is so directed that it passes through the holes. When it comes out it's de-Broglie wavelength is

Two large parallel plates are connected with the terminal of 100 V power supply. These plates have a fine hole at the centre. An electron having energy 200 eV is so directed that it passes through the holes. When it comes out it's de-Broglie wavelength is

If a voltage applied to an X-ray tube is increased to 1.5 times the minimum wavelength $left parenthesis lambda subscript m i n end subscript$ of an X-ray continuous spectrum shifts by $capital delta lambda equals 26 p m$ . The initial voltage applied to the tube is

If a voltage applied to an X-ray tube is increased to 1.5 times the minimum wavelength $left parenthesis lambda subscript m i n end subscript$ of an X-ray continuous spectrum shifts by $capital delta lambda equals 26 p m$ . The initial voltage applied to the tube is

$f open parentheses x close parentheses equals open square brackets x minus 5 close square brackets plus open square brackets 5 minus x close square brackets blank$ is continuous on

$f open parentheses x close parentheses equals open square brackets x minus 5 close square brackets plus open square brackets 5 minus x close square brackets blank$ is continuous on

The value of f (0) so that f(x) = $open parentheses 1 plus 5 x close parentheses to the power of 1 divided by x end exponent$ is continuous at x = 0 is

The value of f (0) so that f(x) = $open parentheses 1 plus 5 x close parentheses to the power of 1 divided by x end exponent$ is continuous at x = 0 is

$fraction numerator t a n blank 80 to the power of 0 end exponent blank minus blank t a n blank 10 to the power of 0 end exponent over denominator t a n invisible function application 70 to the power of 0 end exponent blank end fraction$

$fraction numerator t a n blank 80 to the power of 0 end exponent blank minus blank t a n blank 10 to the power of 0 end exponent over denominator t a n invisible function application 70 to the power of 0 end exponent blank end fraction$

With Turito Academy.

With Turito Foundation.

Get an Expert Advice From Turito.

Turito Academy

With Turito Academy.

Test Prep

With Turito Foundation.

Courses

Quick Links

Follow Us at

Support

Download App

Courses

Quick Links

Have a query? Ask a Tutor!!

Can’t find what you’re looking for?

A beam of fast moving alpha particles were directed towards a thin film of gold. The parts and of the transmitted and reflected beams corresponding to the incident parts A, B and C of the beam, are shown in the adjoining diagram. The number of alpha particles in

'/>will be minimum and in '/>maximum '/>will be maximum and in '/>minimum '/>will be minimum and in '/>maximum '/>will be minimum and in '/>maximum

The correct answer is: will be maximum and in minimum

Because atom is hollow and whole mass of atom is concentrated in a small centre called nucleus.

Related Questions to study

The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength is emitted. The wavelength of photon produced during its transition from level to E is

The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength is emitted. The wavelength of photon produced during its transition from level to E is

Energy levels A, B, C of a certain atom corresponding to increasing values of energy i.e. . If are the wavelengths of radiations corresponding to the transitions C to B, B to A and C to A respectively, which of the following statements is correct

Energy levels A, B, C of a certain atom corresponding to increasing values of energy i.e. . If are the wavelengths of radiations corresponding to the transitions C to B, B to A and C to A respectively, which of the following statements is correct

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

The energy levels of the hydrogen spectrum is shown in figure. There are some transitions A, B, C, D and E. Transition A, B and C respectively represent

The energy levels of the hydrogen spectrum is shown in figure. There are some transitions A, B, C, D and E. Transition A, B and C respectively represent

In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number)

In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number)

If the potential difference between the anode and cathode of the X-ray tube is increases

If the potential difference between the anode and cathode of the X-ray tube is increases

Two large parallel plates are connected with the terminal of 100 V power supply. These plates have a fine hole at the centre. An electron having energy 200 eV is so directed that it passes through the holes. When it comes out it's de-Broglie wavelength is

Two large parallel plates are connected with the terminal of 100 V power supply. These plates have a fine hole at the centre. An electron having energy 200 eV is so directed that it passes through the holes. When it comes out it's de-Broglie wavelength is

Light of wavelength 2475 Å is incident on barium. Photoelectrons emitted describe a circle of radius 100 cm by a magnetic field of flux density Tesla. Work function of the barium is (Given

Light of wavelength 2475 Å is incident on barium. Photoelectrons emitted describe a circle of radius 100 cm by a magnetic field of flux density Tesla. Work function of the barium is (Given

If a voltage applied to an X-ray tube is increased to 1.5 times the minimum wavelength of an X-ray continuous spectrum shifts by . The initial voltage applied to the tube is

If a voltage applied to an X-ray tube is increased to 1.5 times the minimum wavelength of an X-ray continuous spectrum shifts by . The initial voltage applied to the tube is

The figure shows different graphs between stopping potential and frequency (n) for photosensitive surface of cesium, potassium, sodium and lithium. The plots are parallel. Correct ranking of the targets according to their work function greatest first will be

The figure shows different graphs between stopping potential and frequency (n) for photosensitive surface of cesium, potassium, sodium and lithium. The plots are parallel. Correct ranking of the targets according to their work function greatest first will be

f(x) = is continuous at x = 2 then k =

f(x) = is continuous at x = 2 then k =

is continuous on

is continuous on

The value of f (0) so that f(x) = is continuous at x = 0 is

The value of f (0) so that f(x) = is continuous at x = 0 is

Ifthen atis

Ifthen atis

With Turito Academy.

With Turito Foundation.

Get an Expert Advice From Turito.

Turito Academy

With Turito Academy.

Test Prep

With Turito Foundation.

Courses

Quick Links

$B^{}$ '/>will be minimum and in $C^{}$ '/>maximum
$A^{}$ '/>will be maximum and in $B^{}$ '/>minimum
$A^{}$ '/>will be minimum and in $B^{}$ '/>maximum
$C^{}$ '/>will be minimum and in $B^{}$ '/>maximum

The correct answer is: $A to the power of ´ end exponent$ will be maximum and in $B to the power of ´ end exponent$ minimum

The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength $lambda$ is emitted. The wavelength of photon produced during its transition from $fraction numerator 4 E over denominator 3 end fraction$ level to E is

The following diagram indicates the energy levels of a certain atom when the system moves from 2E level to E, a photon of wavelength $lambda$ is emitted. The wavelength of photon produced during its transition from $fraction numerator 4 E over denominator 3 end fraction$ level to E is

If a voltage applied to an X-ray tube is increased to 1.5 times the minimum wavelength $left parenthesis lambda subscript m i n end subscript$ of an X-ray continuous spectrum shifts by $capital delta lambda equals 26 p m$ . The initial voltage applied to the tube is

If a voltage applied to an X-ray tube is increased to 1.5 times the minimum wavelength $left parenthesis lambda subscript m i n end subscript$ of an X-ray continuous spectrum shifts by $capital delta lambda equals 26 p m$ . The initial voltage applied to the tube is

$f open parentheses x close parentheses equals open square brackets x minus 5 close square brackets plus open square brackets 5 minus x close square brackets blank$ is continuous on

$f open parentheses x close parentheses equals open square brackets x minus 5 close square brackets plus open square brackets 5 minus x close square brackets blank$ is continuous on

The value of f (0) so that f(x) = $open parentheses 1 plus 5 x close parentheses to the power of 1 divided by x end exponent$ is continuous at x = 0 is

The value of f (0) so that f(x) = $open parentheses 1 plus 5 x close parentheses to the power of 1 divided by x end exponent$ is continuous at x = 0 is