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Physics-

General

Easy

Question

A body is projected horizontally from the top of a high tower with a speed of 20 m/s. After 4 sec the displacement of the body is (take g=10m/s²)

40 m
80m
80 $\sqrt{2}$ m
80/ $\sqrt{2}$ m

The correct answer is: 80 $square root of 2$ m

Related Questions to study

Consider the reaction: $blank C l subscript 2 end subscript left parenthesis a q right parenthesis plus H subscript 2 end subscript S left parenthesis a q right parenthesis ⟶ S left parenthesis s right parenthesis plus 2 H to the power of plus end exponent left parenthesis a q right parenthesis plus 2 C l to the power of minus end exponent left parenthesis a q right parenthesis$ The rate equation for this reaction is : $blank R a t e blank equals k open square brackets C l subscript 2 end subscript close square brackets open square brackets H subscript 2 end subscript S close square brackets$ Which of these mechanisms is/are consistent with this rate equation ?

Consider the reaction: $blank C l subscript 2 end subscript left parenthesis a q right parenthesis plus H subscript 2 end subscript S left parenthesis a q right parenthesis ⟶ S left parenthesis s right parenthesis plus 2 H to the power of plus end exponent left parenthesis a q right parenthesis plus 2 C l to the power of minus end exponent left parenthesis a q right parenthesis$ The rate equation for this reaction is : $blank R a t e blank equals k open square brackets C l subscript 2 end subscript close square brackets open square brackets H subscript 2 end subscript S close square brackets$ Which of these mechanisms is/are consistent with this rate equation ?

Chemistry-General

Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at one point and moved with velocities V₁ = 1 m/s and V₂ = 4 m/s horizontally in opposite directions. The distance between the particles at the moment when their velocity vectors become mutually perpendicular is (g=10m/s²)

Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located at one point and moved with velocities V₁ = 1 m/s and V₂ = 4 m/s horizontally in opposite directions. The distance between the particles at the moment when their velocity vectors become mutually perpendicular is (g=10m/s²)

Physics-General

An endothermic reaction with high activation energy for the forward reaction is given by the diagram:

An endothermic reaction with high activation energy for the forward reaction is given by the diagram:

Chemistry-General

parallel

Graph between concentration of the product' x' and time' t' for $A rightwards arrow B$ is given ahead:
The graph between $negative fraction numerator d left square bracket A right square bracket over denominator d t end fraction$ and time wil1 be of the type:

Graph between concentration of the product' x' and time' t' for $A rightwards arrow B$ is given ahead:
The graph between $negative fraction numerator d left square bracket A right square bracket over denominator d t end fraction$ and time wil1 be of the type:

Chemistry-General

Following is the graph between $left parenthesis a minus x right parenthesis to the power of negative 1 end exponent$ and time t for second order reaction. $theta equals t a n to the power of negative 1 end exponent invisible function application left parenthesis 1 divided by 2 right parenthesis semicolon O A equals 2 L m o l to the power of negative 1 end exponent$ hence rate at the start of reaction will be:

Following is the graph between $left parenthesis a minus x right parenthesis to the power of negative 1 end exponent$ and time t for second order reaction. $theta equals t a n to the power of negative 1 end exponent invisible function application left parenthesis 1 divided by 2 right parenthesis semicolon O A equals 2 L m o l to the power of negative 1 end exponent$ hence rate at the start of reaction will be:

Chemistry-General

Following is the graph between log tll2 and log a (a = initial concentration) for a given
reaction at $27 to the power of ring operator end exponent$ e. Hence, order is:

Following is the graph between log tll2 and log a (a = initial concentration) for a given
reaction at $27 to the power of ring operator end exponent$ e. Hence, order is:

Chemistry-General

parallel

For the reaction $N H subscript 4 end subscript superscript plus end superscript plus O C N ⟶ N H subscript 2 end subscript C O N H subscript 2 end subscript$ the probable mechanism is,
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell NH subscript 4 superscript plus plus OCN to the power of minus not stretchy rightwards harpoon over leftwards harpoon NH subscript 4 OCN end cell row cell text and end text space of 1em NH subscript 4 OCN not stretchy ⟶ NH subscript 2 CONH subscript 2 space of 1em text (slow) end text end cell end table$ The rate law will be:

For the reaction $N H subscript 4 end subscript superscript plus end superscript plus O C N ⟶ N H subscript 2 end subscript C O N H subscript 2 end subscript$ the probable mechanism is,
$table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell NH subscript 4 superscript plus plus OCN to the power of minus not stretchy rightwards harpoon over leftwards harpoon NH subscript 4 OCN end cell row cell text and end text space of 1em NH subscript 4 OCN not stretchy ⟶ NH subscript 2 CONH subscript 2 space of 1em text (slow) end text end cell end table$ The rate law will be:

Chemistry-General

A drop of solution (volume 0.05 mL) contains $3 cross times 10 to the power of negative 6 end exponent$ mole of W. If the rate constant of disappearance of H+ is 107 mol $text litre end text to the power of negative 1 end exponent sec to the power of negative 1 end exponent$ , how long would it take for W in the drop tell disappear?

A drop of solution (volume 0.05 mL) contains $3 cross times 10 to the power of negative 6 end exponent$ mole of W. If the rate constant of disappearance of H+ is 107 mol $text litre end text to the power of negative 1 end exponent sec to the power of negative 1 end exponent$ , how long would it take for W in the drop tell disappear?

Chemistry-General

P₄ + 5O₂ ¾ → X $Error converting from MathML to accessible text.$ Y, Y is

P₄ + 5O₂ ¾ → X $Error converting from MathML to accessible text.$ Y, Y is

Chemistry-General

parallel

Cu²⁺ + 2e^– ¾® Cu; log[Cu²⁺] vs E_red graph is of the type shown in figure where OA = 0.34V, then electrode potential of the half cell of Cu/Cu²⁺ (0.1 M) will be

Cu²⁺ + 2e^– ¾® Cu; log[Cu²⁺] vs E_red graph is of the type shown in figure where OA = 0.34V, then electrode potential of the half cell of Cu/Cu²⁺ (0.1 M) will be

Chemistry-General

Which statement is correct for alkaline earth metals

Which statement is correct for alkaline earth metals

Chemistry-General

The incorrect statement is

The incorrect statement is

Chemistry-General

parallel

Ketone can be prepared by

Ketone can be prepared by

Chemistry-General

Chemistry-General

Chemistry-General

parallel

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