Physics-
General
Easy

Question

A coil has L = 0.04 H and R equals 12 capital omega. When it is connected to 220V, 50Hz supply the current flowing through the coil, in amperes is

  1. 10.7    
  2. 11.7    
  3. 14.7    
  4. 12.7    

The correct answer is: 12.7


    Impedance Z equals square root of R to the power of 2 end exponent plus 4 pi to the power of 2 end exponent nu to the power of 2 end exponent L to the power of 2 end exponent end root
    equals square root of left parenthesis 12 right parenthesis to the power of 2 end exponent plus 4 cross times left parenthesis 3.14 right parenthesis to the power of 2 end exponent cross times left parenthesis 50 right parenthesis to the power of 2 end exponent cross times left parenthesis 0.04 right parenthesis end root= 17.37 A
    Now current i equals fraction numerator V over denominator Z end fraction equals fraction numerator 220 over denominator 17.37 end fraction equals 12.7 capital omega

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