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Physics-

General

Easy

Question

A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 rad $blank s to the power of negative 1 end exponent$ . If the horizontal component of earth’s magnetic field is $0.2 cross times 10 to the power of negative 4 end exponent blank T comma$ then the emf developed between the two ends of the conductor is

5 $Μ v$
50 $μ V$
5 mV
50 mV

The correct answer is: 50 $blank mu V$

The emf induced betweenends of conductor
$e equals fraction numerator 1 over denominator 2 end fraction B omega L to the power of 2 end exponent$
$equals fraction numerator 1 over denominator 2 end fraction cross times 0.2 cross times 10 to the power of negative 4 end exponent cross times 5 cross times open parentheses 1 close parentheses to the power of 2 end exponent$
$equals 0.5 cross times 10 to the power of negative 4 end exponent V$
$equals 5 cross times 10 to the power of negative 5 end exponent V equals 50 mu V$

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