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.A pair of parallel conducting rails lie at right angles to a uniform magnetic field of 2.0 blank T as shown in the fig. Two resistors 10 blank capital omega and 5 blank capital omega are to slide without friction along the rail. The distance between the conducting rails is 0.1 blank m. Then

  1. Induced current equals fraction numerator 1 over denominator 150 end fraction A directed clockwise if 10 blank capital omega resistor is pulled to the right with speed 0.5 blank m s to the power of negative 1 end exponent and 5 capital omega resistor is held fixed  
  2. Induced current equals fraction numerator 1 over denominator 300 end fraction A directed anti-clockwise if 10 blank capital omega resistor is pulled to the right with speed 0.5 blank m s to the power of negative 1 end exponent and 5 capital omega resistor is held fixed  
  3. Induced current equals fraction numerator 1 over denominator 300 end fraction A directed clockwise if 5 blank capital omega resistor is pulled to the left at 0.5 blank m s to the power of negative 1 end exponent and 10 capital omega resistor is held at rest  
  4. Induced current equals fraction numerator 1 over denominator 150 end fraction A directed anti-clockwise if 5 blank capital omega resistor is pulled to the left at 0.5 blank m s to the power of negative 1 end exponent and 10 capital omega resistor is held at rest  

The correct answer is: Induced current equals fraction numerator 1 over denominator 150 end fraction A directed anti-clockwise if 5 blank capital omega resistor is pulled to the left at 0.5 blank m s to the power of negative 1 end exponent and 10 capital omega resistor is held at rest


    resistor is pulled left at 0.5 blank m divided by s e c induced e m f in the said resistor equals e equals v B l equals 0.5 cross times 2 cross times 0.1 equals 0.1 blank V
    Resistor 10 capital omega is at rest so induced e m f in it left parenthesis e equals v B l right parenthesis be zero
    Now net e m f in the circuit equals 0.1 V and equivalent resistance of the circuit R equals 15 capital omega
    Hence current i equals fraction numerator 0.1 over denominator 15 end fraction a m p equals fraction numerator 1 over denominator 150 end fraction a m p
    And its direction will be anti-clockwise (according to Lenz’s law)

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