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General
Easy

Question

A pendulum of length 2m lift at P. When it reaches Q, it losses 10% of its total energy due to air resistance. The velocity at Q is

  1. 6 m/se c    
  2. 1 m/sec    
  3. 2 m/sec    
  4. 8 m/sec    

The correct answer is: 6 m/se c


    If v is velocity of pendulum at Q
    and 10% energy is lost while moving from P to Q
    Hence, by applying conservation of between P and Q
    fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent equals 0.9 left parenthesis m g h right parenthesis Þv to the power of 2 end exponent equals 2 cross times 0.9 cross times 10 cross times 2Þ v equals 6 m divided by s e c

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