Physics
Mechanics
Easy
Question
A satellite is revolving around the earth in a circular orbit of radius a with velocity . A particle is projected from the satellite in forward direction with relative velocity 
. During the subsequent motion of the particle, match the following:
Column I
Column II
i. Total energy of particle
a.
ii. Minimum distance of particle from the earth
b. 
iii. Maximum distance of particle from the earth
c. 
d. 2a
e. 2 a/3
f. a
|
Column I |
Column II |
| i. Total energy of particle |
a. |
| ii. Minimum distance of particle from the earth |
b. |
| iii. Maximum distance of particle from the earth |
c. |
| |
d. 2a |
| |
e. 2 a/3 |
| |
f. a |
- i. → b; ii. → d; iii. → c
- i. → a; ii. → f; iii. → c
- i. → f; ii. → b; iii. → c
- i. → a; ii. → f; iii. → e
The correct answer is: i. → a; ii. → f; iii. → c
Angular momentum of the particle 
Total energy of the particle 
At any distance 
But angular momentum conservation gives
Minimum distance = a
Maximum distance 
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Let V and E denote the gravitational potential and gravitational field, respectively, at a point due to certain uniform mass distribution described in four different situations of Column I. Assume the gravitational potential at infinity to be zero. The values of E and V are given in Column II Match the statement in column I with the results in Column II.
|
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Column II |
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Let V and E denote the gravitational potential and gravitational field, respectively, at a point due to certain uniform mass distribution described in four different situations of Column I. Assume the gravitational potential at infinity to be zero. The values of E and V are given in Column II Match the statement in column I with the results in Column II.
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