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Question

A TV tower has a height of 100 m. How much population is covered by the TV broadcast if the average population density around the tower is 100 blank k m to the power of negative 2 end exponent(radius of the earthequals 6.37 cross times 10 to the power of 6 end exponent m)

  1. 4 lakh  
  2. 4 billion  
  3. 40,000  
  4. 40 lakh  

The correct answer is: 40 lakh


    d equals square root of 2 h R end root
    Population covered
    equals pi d to the power of 2 end exponent cross timespopulation density
    equals 3.114 cross times left parenthesis 2 cross times 0.1 cross times 6.37 cross times 10 to the power of 3 end exponent right parenthesis cross times 1000 almost equal to 40 lakh

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