Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If in $blank increment A B C comma sin invisible function application A cos invisible function application B equals fraction numerator square root of 2 minus 1 over denominator square root of 2 end fraction$ and $sin invisible function application B cos invisible function application A equals fraction numerator 1 over denominator square root of 2 end fraction comma blank$ then the triangle is

Equilateral
Isosceles
Right angled
Right-angled isosceles

The correct answer is: Right angled

Adding, $sin invisible function application open parentheses A plus B close parentheses equals 1$
and subtracting, $sin invisible function application open parentheses A minus B close parentheses equals fraction numerator square root of 2 minus 2 over denominator square root of 2 end fraction equals 1 minus square root of 2 not equal to 0$
$therefore A plus B equals 90 degree comma blank A not equal to B$

Related Questions to study

The equation $2 cos to the power of 2 end exponent invisible function application fraction numerator x over denominator 2 end fraction sin to the power of 2 end exponent invisible function application x equals x to the power of 2 end exponent equals x to the power of negative 2 end exponent semicolon 0 less than x less or equal than fraction numerator pi over denominator 2 end fraction$ has

The equation $2 cos to the power of 2 end exponent invisible function application fraction numerator x over denominator 2 end fraction sin to the power of 2 end exponent invisible function application x equals x to the power of 2 end exponent equals x to the power of negative 2 end exponent semicolon 0 less than x less or equal than fraction numerator pi over denominator 2 end fraction$ has

If $sin invisible function application x plus c o s e c blank x equals 2 comma$ then $sin to the power of n end exponent invisible function application x plus blank c o s e c to the power of n end exponent x$ is equal to

If $sin invisible function application x plus c o s e c blank x equals 2 comma$ then $sin to the power of n end exponent invisible function application x plus blank c o s e c to the power of n end exponent x$ is equal to

In triangle $A B C comma blank$ if $tan invisible function application open parentheses A divided by 2 close parentheses equals 5 divided by 6$ and $tan invisible function application open parentheses B divided by 2 close parentheses equals 20 divided by 37 comma blank$ the sides $a comma blank b blank$ and $blank c$ are in

In triangle $A B C comma blank$ if $tan invisible function application open parentheses A divided by 2 close parentheses equals 5 divided by 6$ and $tan invisible function application open parentheses B divided by 2 close parentheses equals 20 divided by 37 comma blank$ the sides $a comma blank b blank$ and $blank c$ are in

parallel

$cos to the power of 3 end exponent invisible function application x sin invisible function application 2 x equals not stretchy sum from x equals 0 to n of a subscript r end subscript sin invisible function application open parentheses r blank x close parentheses for all x element of R comma blank t h e n$

$cos to the power of 3 end exponent invisible function application x sin invisible function application 2 x equals not stretchy sum from x equals 0 to n of a subscript r end subscript sin invisible function application open parentheses r blank x close parentheses for all x element of R comma blank t h e n$

If the equation $cot to the power of 4 end exponent invisible function application x minus 2 blank c o s e c to the power of 2 end exponent blank x plus a to the power of 2 end exponent equals 0$ has at least one solution, then the sum of all possible integral values of $´ a to the power of ´ end exponent$ is equal to

If the equation $cot to the power of 4 end exponent invisible function application x minus 2 blank c o s e c to the power of 2 end exponent blank x plus a to the power of 2 end exponent equals 0$ has at least one solution, then the sum of all possible integral values of $´ a to the power of ´ end exponent$ is equal to

Let $blank f open parentheses n close parentheses equals 2 cos invisible function application n x for all n element of N comma blank t h e n blank f open parentheses 1 close parentheses blank f open parentheses n plus 1 close parentheses minus f open parentheses n close parentheses$ is equal to

Let $blank f open parentheses n close parentheses equals 2 cos invisible function application n x for all n element of N comma blank t h e n blank f open parentheses 1 close parentheses blank f open parentheses n plus 1 close parentheses minus f open parentheses n close parentheses$ is equal to

parallel

In any triangle $A B C comma sin to the power of 2 end exponent invisible function application A minus sin to the power of 2 end exponent invisible function application B plus sin to the power of 2 end exponent invisible function application C$ is always equal to

In any triangle $A B C comma sin to the power of 2 end exponent invisible function application A minus sin to the power of 2 end exponent invisible function application B plus sin to the power of 2 end exponent invisible function application C$ is always equal to

The number of solution of $sin to the power of 4 end exponent invisible function application x minus cos to the power of 2 end exponent invisible function application x sin invisible function application x plus 2 sin to the power of 2 end exponent invisible function application x plus sin invisible function application x equals 0$ in $0 less or equal than x less or equal than 3 pi$ is

The number of solution of $sin to the power of 4 end exponent invisible function application x minus cos to the power of 2 end exponent invisible function application x sin invisible function application x plus 2 sin to the power of 2 end exponent invisible function application x plus sin invisible function application x equals 0$ in $0 less or equal than x less or equal than 3 pi$ is

The range of $k$ for which the inequality $k cos to the power of 2 end exponent invisible function application x minus k cos invisible function application x plus 1 greater or equal than 0 blank for all x element of open parentheses negative infinity comma infinity close parentheses comma$ is

The range of $k$ for which the inequality $k cos to the power of 2 end exponent invisible function application x minus k cos invisible function application x plus 1 greater or equal than 0 blank for all x element of open parentheses negative infinity comma infinity close parentheses comma$ is

parallel

In triangle $A B C$ , angle $A$ is greater than angle $B$ . If the measures of angles $A$ and $B$ satisfy the equation $3 sin invisible function application x minus 4 sin to the power of 3 end exponent invisible function application x minus k equals 0 comma 0 less than k less than 1$ , then the measure of angle $C$ is

In triangle $A B C$ , angle $A$ is greater than angle $B$ . If the measures of angles $A$ and $B$ satisfy the equation $3 sin invisible function application x minus 4 sin to the power of 3 end exponent invisible function application x minus k equals 0 comma 0 less than k less than 1$ , then the measure of angle $C$ is

In triangle $A B C$ if angle $C$ is $90 degree$ and area of triangle is 30 sq. units, then the minimum possible value of the hypotenuse $c$ is equal to

In triangle $A B C$ if angle $C$ is $90 degree$ and area of triangle is 30 sq. units, then the minimum possible value of the hypotenuse $c$ is equal to

The current $i$ in a coil varies with time as shown in the figure. The variation of induced emf with time would be

The current $i$ in a coil varies with time as shown in the figure. The variation of induced emf with time would be
Physics-General

parallel

Two different loops are concentric and lie in the same plane. The current in the outer loop is clockwise and increasing with time. The induced current in the inner loop then, is

Two different loops are concentric and lie in the same plane. The current in the outer loop is clockwise and increasing with time. The induced current in the inner loop then, is

Physics-General

The magnitude of the earth’s magnetic field at a place is $B subscript 0 end subscript$ and the angle of dip is $delta.$ A horizontal conductor of length $l comma$ lying north-south, moves eastwards with a velocity $v$ . The emf induced across the rod is

The magnitude of the earth’s magnetic field at a place is $B subscript 0 end subscript$ and the angle of dip is $delta.$ A horizontal conductor of length $l comma$ lying north-south, moves eastwards with a velocity $v$ . The emf induced across the rod is

Physics-General

If in a coil rate of change of area is $fraction numerator 5 blank m e t r e to the power of 2 end exponent over denominator m i l l i blank s e c o n d end fraction$ , current becomes $1 blank a m p$ form $2 blank a m p$ in $2 cross times 10 to the power of negative 3 end exponent s e c$ magnetic field is $1 blank t e s l a$ , then self inductance of the coil is

If in a coil rate of change of area is $fraction numerator 5 blank m e t r e to the power of 2 end exponent over denominator m i l l i blank s e c o n d end fraction$ , current becomes $1 blank a m p$ form $2 blank a m p$ in $2 cross times 10 to the power of negative 3 end exponent s e c$ magnetic field is $1 blank t e s l a$ , then self inductance of the coil is

Physics-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.