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Physics

Fluid-Mechanics

Easy

Question

A uniformly tapering vessel of height h whose lower and upper radii are r and R is completely filled with a liquid of density $rho$ . The force that acts on the base of the vessel due of the liquid is

$π R^{2} h ρ g$
$π r^{2} h ρ g$
$π {(\frac{R + r}{2})}^{2} h ρ g$
$\frac{1}{3} π (R^{2} - r^{2}) h ρ g$

The correct answer is: $pi r squared h rho g$

Force = area of base \times pressure due to liquid column of height $h equals pi to the power of r squared end exponent cross times h rho g$

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