Physics-
General
Easy
Question
All six capacitors shown are identical, Each can withstand maximum 200 volts between its terminals. The maximum voltage that can be safely applied between A and B is
- 1200 V
- 400 V
- 800 V
- 200 V
The correct answer is: 400 V
Given circuit can be reduced as follows
(C = capacitance of each capacitor)
The capacitor 3C, 3C shown in figure can with stand maximum 200 V.
\ So maximum voltage that can be applied across A and B equally shared. Hence maximum voltage applied cross A and B be equally shared. Hence max. voltage applied across A and B will be (200 + 200) = 400 volt.
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